Triangles are similar and only differ in size meaning they are dilated
So first we have to find the scale factor of dilation (by how much the smaller triangle got bigger)
Find scale factor:
2.4a=4.8
z=2
Find x:
we multiply the original side of the small side with the scale factor of 2
2.8(2)=x
5.6=x
So, x=5.6
Each graph has been matched with the logarithmic function it represents as follows:
- f(x) = 3 - 4In (x-2) = graph 3.
- f(x) = 3 - Inx = graph 1.
- f(x) = In(x + 1) = graph 4.
- f(x) = 2In(x + 3) = graph 2.
<h3>What is a function?</h3>
A function can be defined as a mathematical expression which is used to define and represent the relationship that exists between two or more variables.
<h3>The types of function.</h3>
In Mathematics, there are different types of functions and these include the following;
- Piece-wise defined function.
<h3>What is a logarithm function?</h3>
A logarithm function can be defined as a type of function that represents the inverse of an exponential function. Mathematically, a logarithm function is written as follows:
y = logₐₓ
In this exercise, you're required to match each graph with the logarithmic function it represents as shown in the image attached below:
- f(x) = 3 - 4In (x-2) = graph 3.
- f(x) = 3 - Inx = graph 1.
- f(x) = In(x + 1) = graph 4.
- f(x) = 2In(x + 3) = graph 2.
Read more on logarithm function here: brainly.com/question/13473114
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Answer:
The correct option is 4.
Step-by-step explanation:
The given function is

Where f(x) is height of the ball and x is the distance.
It is a polynomial function with degree 2. All polynomial functions are defined for all real numbers, therefore the mathematical domain of the function is all real numbers.

Factorize the given function.





Put f(x)=0 to find the x intercepts.

Equate each factor equal to 0.

Therefore at x=52 and -2, the graph of f(x) intersects x-axis. Before x=-2 and after x=52 the values of f(x) is negative. Height cannot be negative, therefore reasonable domain is lie between -2 to 52.
Distance cannot be negative, therefore the reasonable domain must be positive.

Therefore the reasonable domain is
and option 4 is correct.