Question

Choose the equation below whose axis of symmetry is x = 0. (1 point) y = x2 + 2x y = x2 − 16x + 58 y = x2 + 2 y = x2 − 4x + 2

Answer 1

Answer:

y=x^2+2

Step-by-step explanation:

Quadratic function has a general function:

$y=ax^2+bx+c$

And you can calculate the axis of symmetry with:

x1=-b/2a

Then you calculate the axis for each equation:

1. y = x^2 + 2x

x1=-2/(2*1)=-1

2.  y = x^2 − 16x + 58

x1=-(-16)/(2*1)=8

3. y = x^2 + 2

notice: you don't have b term

x1=-0/(2*1)=0

4. y = x ^2 − 4x + 2

x1=-(-4)/(2*1)=2

Answer 2

The equation y = x^2 has axis of symmetry of  x = 0

The answer to the question is y = x^2 + 2  which is y = x^2 moved vertically up to 2 units