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liraira [26]
3 years ago
8

The data to the right represent the top speed (in kilometers per hour) Of all the players (except goaltenders) in a certain socc

er league. Construct (a) a relative frequency distribution (b) a frequency histogram, and (c) a relative frequency histogram. What percentage of players had a top speed between 22 and 25 9 km/h? What percentage of players had a top speed between 26 and 29.9​km/h?Speed(Km/hr) Number of players10--13.9 414-17.9 718-21.9 2022-25.9 83 26-29.9 31930-33.9 179 a. Construct a relative frequency distributionb. The percentage of players that had a top speed between 22 and 25.9 km/h was :______c. The percentage of players that had a top speed less than 13.9 km/h was:_________
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Speed(Km/hr)___No of players__Relative freq

10--13.9_________4______4/612 = 0.0065359

14-17.9_________ 7______7/612 = 0.0114379

18-21.9________20_____20/612 = 0.0326797

22-25.9_______ 83_____83/612 = 0.1356209

26-29.9_______319____319/612 =0.5212418

30-33.9______ 179_____179/612 = 0.2924836

The percentage of players that had a top speed between 22 and 25.9 km/h was : 0.1356209 × 100 = 13.56%

c. The percentage of players that had a top speed less than 13.9 km/h was: 0.0065359 × 100 = 0.65%

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The ordered pair (6 , 4) is a solution for y - 4 = 7(x - 6)

Step-by-step explanation:

The point-slope form of a linear equation is:

y-y_{1}=m(x-x_{1}) , where

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  • (x_{1},y_{1}) is a point on the line

Any point on the line is a solution for the equation of the line

The solution of an equation is the values of x and y which make the left hand side is equal to the right hand side

∵ The equation is y - 4 = 7(x - 6)

- Compare the equation by the point-slope form above

∴ m = 7

∴ x_{1} = 6 and y_{1} = 4

- That means point (6 , 6) lies on the line

∴ Point (6 , 4) is a point on the line which represents the

   given equation

∵ Any point on a line is a solution of the equation of that line

∴ (6 , 4) is a solution of the equation

The ordered pair (6 , 4) is a solution for y - 4 = 7(x - 6)

Learn more:

You can learn more about the linear equations in brainly.com/question/1284310

#LearnwithBrainly

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3 years ago
A 6-sided die with sides numbered 1 through 6 is tossed. A penny is then tossed. If the penny comes up heads, the value of the d
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Answer:

The probability that the outcome is less than 6 is 58.333%.

Step-by-step explanation:

Since a 6-sided die with sides numbered 1 through 6 is tossed, ya penny is then tossed, and if the penny comes up heads, the value of the die is multiplied by 2, but otherwise, the value of the die is left unchanged, to determine what is the probability that the outcome is less than 6 the following calculation must be performed:

(5/6 + 2/6) / 2 = X

(0.8333 + 0.0333) / 2 = X

1.1666666 / 2 = X

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Therefore, the probability that the outcome is less than 6 is 58.333%.

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Step-by-step explanation:

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3 years ago
A small plane took 3 hours to fly 960 km from Ottawa to Halifax with a tail wind. On the return trip, flying into the wind, the
Rina8888 [55]

Answer:

  • Wind speed: \rm 40\; km \cdot h^{-1}.
  • Speed of the plane in still air: \rm 320\; km \cdot h^{-1}.

Step-by-step explanation:

This problem involves two unknowns:

  • wind speed, and
  • speed of the plane in still air.

Let the speed of the wind be x \rm \; km \cdot h^{-1}, and the speed of the plane in still air be y\rm \; km \cdot h^{-1}. It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

  • It takes the plane three hours to travel \rm 960\; km from Ottawa to with a tail wind (that is: at a ground speed of x + y.)
  • It takes the plane four hours to travel \rm 960\; km from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of -x + y.)

Create a two-by-two system out of these two equations:

\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right..

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right..

\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right..

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only 1 \times 960 on the right-hand side. In comparison, adding them will give 7 \times 960, which is much more complex to evaluate. Subtracting the second equation (3 \times (2)) from the first (4 \times (1)) will give the equation

(12 - (-12) x = 1 \times 960.

24 x = 960.

x = 40.

Substitute x back into either equation (1) or (2) of the original system. Solve for y to obtain y = 320.

In other words,

  • Wind speed: \rm 40\; km \cdot h^{-1}.
  • Speed of the plane in still air: \rm 320\; km \cdot h^{-1}.
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