1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna [14]
3 years ago
5

A survey showed that 77​% of adults need correction​ (eyeglasses, contacts,​ surgery, etc.) for their eyesight. If 22 adults are

randomly​ selected, find the probability that no more than more than 11 of them need correction for their eyesight. Is 11 a significantly low low number of adults requiring eyesight​ correction?
Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight​ correction .

Step-by-step explanation:

A survey showed that 77​% of adults need correction for their eyesight.

If 22 adults are randomly​ selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find P(x\leq 11)

P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)

Formula : P(x=r)=^nC_r p^r q^{n-r}

P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}

Using calculator

P(x\leq 11)=0.00512

So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight​ correction .

You might be interested in
If this figure is dilated by a scale factor of 3, what would the new coordinates be?
QveST [7]

Answer:

J (-3,3), G (0,3), H (4,9), I (3,3)

Step-by-step explanation:

When your dilating a figuring it either gets larger or smaller. Since this is a positive number, and it is not a fraction then the figure is getting larger. Now you multiply each of the original coordinates by 3 to get the dilated coordinates.

(For learning purposes only)

8 0
3 years ago
Find the solution to the boundary value problem: d2ydt2−7dydt+10y=0, y(0)=6,y(1)=3
Angelina_Jolie [31]
Try this solution. Basic steps marked by '·'
You may simplify the answer.

8 0
4 years ago
9/10 divided by 3/5
Sever21 [200]

Answer:

1 1/2

Step-by-step explanation:

9/10 ÷ 3/5

Copy dot flip

9/10 * 5/3

Rewriting

9/3 * 5/10

3 * 1/2

3/2

1 1/2

7 0
3 years ago
Read 2 more answers
Verify the following trigonometric identity: (csc x + cot x)^2 = cos x +1/ 1- cos x
Airida [17]

9514 1404 393

Explanation:

As written, the equation is not an identity. Perhaps you want to show ...

  (csc(x) +cot(x))² = (cos(x) +1)/(1 -cos(x))

__

We will transform the left-side expression to the form of the right-side expression.

  (\csc(x)+\cot(x))^2=\left(\dfrac{1}{\sin(x)}+\dfrac{\cos(x)}{\sin(x)}\right)^2=\dfrac{(1+\cos(x))^2}{\sin(x)^2}\\\\=\dfrac{(1+\cos(x))^2}{1-\cos(x)^2}=\dfrac{1+\cos(x)}{1-\cos(x)}\cdot\dfrac{1+\cos(x)}{1+\cos(x)}=\boxed{\dfrac{\cos(x)+1}{1-\cos(x)}}

3 0
3 years ago
Find the value of 9!/ (9-2)!
dem82 [27]

Answer:

<h2>72</h2>

Step-by-step explanation:

n!=1\cdot2\cdot3\cdot...\cdot n\\\\\dfrac{9!}{(9-2)!}=\dfrac{9!}{7!}=\dfrac{7!\cdot8\cdot9}{7!}\qquad\text{cancel}\ 7!\\\\=8\cdot9=72

5 0
3 years ago
Other questions:
  • What is the sum of twenty and thirty
    14·2 answers
  • Subtract: (2x2 - 6x + 7) - (5x2 + 2x - 8).
    9·1 answer
  • (SAT prep) In △ABC, AB = BC =20, DE ≈ 9.28. Approximate BD.
    10·1 answer
  • PLEASE HELP ME WITH THIS! ASAPI WILL GIVE BRAINLIEST
    12·1 answer
  • a recipe calls for 2/3 of a cup of sugar per batch. elena used 5 and 1/3 cups of sugar to make multiple batches of cookies. How
    7·2 answers
  • Cynthia has earned $1200. She wants to spend $300 and put the rest into a savings
    13·1 answer
  • Which choices are equivalent to the exponential expression below?​
    14·1 answer
  • Someone help now please
    14·2 answers
  • CAN SOMEBODY EXPLAIN HOW TO DO THIS IT'S MY 5TH TIME ASKING AND NOBODY EVEN HELPS ME!
    14·2 answers
  • Please help me asap!!
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!