Total money Marcus has = $28
Money spent to buy a notebook = $3.75
Money left now = 
Money needed to be saved = $11.25
So, the amount of money Marcus can spend = 
Cost of a packet of chips = $1.30
The inequality to determine the maximum number of chips he can buy is:
Let the number of chips Marcus can buy = x
As he cannot spend more than $13 to buy chips so equation becomes:

Solving this we get

Hence, Marcus can buy a maximum of 10 packs of chips and save $11.25
0.5 ,0.6 ,0.7 ,0.8 ,0.9 ,1,1 .1 ,1.2 ,1.3
Answer:
The answer is 7/36.
Step-by-step explanation:
First, you find out how many possible outcomes there are from rolling a pair of dice. On one cube, you can roll a 1,2,3,4,5, or 6; so there are 6 outcomes. Since there are two cubes, you multiply 6 by itself to get a total of 36 possible outcomes. Next, you find the probability of the sum of the numbers rolled being an even number; the possibilities are 2,4,6,8,10, or 12, which is 6/36. The probability of rolling a multiple of 5; the one possibility is just 5, since we already accounted for rolling a 10 as an even number. So that is 1/36. The word <u>or</u> says that we add the two probabilities, so the final answer is 6/36+1/36=7/36.
Answer:
-9.8n + 11.1
Step-by-step explanation:
1. Combine like terms
-5.8n - 4n = -9.8n
3.1 + 8 = 11.1
2. -9.8n +11.1