CAN SOMEBODY EXPLAIN HOW TO DO THIS IT'S MY 5TH TIME ASKING AND NOBODY EVEN HELPS ME!
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Using the t-distribution, it is found that the correct option is:
0.005 < P-value < 0.01, reject the null hypothesis.
<h3>What are the hypothesis tested?</h3>At the null hypothesis, it is tested if the mean of a given population is equal to 85, that is:
We have a left-tailed test, hence, at the alternative hypothesis, it is tested if the mean of the population is less than 85, that is:
The test statistic is of t = -3.018.
Using a t-distribution calculator, with test statistic t = -3.018, 13 - 1 = 12 df and a significance level of 0.01, it is found that the p-value for a left-tailed test is of 0.0051.
The p-value is <u>less than 0.01</u>, hence the null hypothesis is rejected and the correct option is:
0.005 < P-value < 0.01, reject the null hypothesis.
More can be learned about the t-distribution at brainly.com/question/16313918
Answer:
Hope this is correct
Step-by-step explanation:
this is the answer on ap ex
