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navik [9.2K]
4 years ago
12

Can someone please answer this for me?

Mathematics
1 answer:
Ronch [10]4 years ago
8 0

Answer:

1. \\ 2x - 1 + y = 11 \\ y = 4 \\ then \\ 2x - 1 + 4 = 11 \\ 2x = 8 \\ x = 4 \\  \\  2. \\

2x - 1 + 4 = 11

2x = 8

x = 4

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A rectangular made of square tiles measures 8 tiles wide and 10 tiles long what is the length in tiles of a similar rectangle 12
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There’s are ratio which would be 8/10. 12/x should equally 8/10. So it would be 14 tiles long.
3 0
4 years ago
{[20/(8+2)]^6+6}/(4^2/2)
Naddika [18.5K]
So for this problem we need to do order of operations so the very first step that we need to do here is (8+2) because that is the smallest enclosed symbols (8+2)=10 next divide by 20 because that is the next step in the equation which 20/10=2, so now we have {[2]^6+6} and due to order of operations the next step here is to take 2 to the power of 6 which is 64 so now we have {64+6} which is 70 so now we have 70/(4^2/2) and due to order of operations we do the parentheses first and that would mean that we do 4^2 because exponents come after parantheses like so,
70/(16/2) now we do 16/2 because its still inside the paranthesess so 16/2=8 so now we have 70/8 and that equals are end answer of 8.75 Enjoy!=)
7 0
3 years ago
Read 2 more answers
-14.25 + -3.78 - (-5.78) - 3.4 A) -19.65 B) -15.65 C) 1.29 D) 27.21
lutik1710 [3]
The answer is B. -15.65
4 0
3 years ago
Write as a single term: cos(2x) cos(x) + sin(2x) sin(x)
GREYUIT [131]

Answer: cos(x)

Step-by-step explanation:

We have  

sin ( x + y ) = sin(x)*cos(y) + cos(x)*sin(y)   (1)   and

cos ( x + y ) = cos(x)*cos(y) - sin(x)*sin(y)  (2)

From eq. (1)

if x = y

sin ( x + x ) = sin(x)*cos(x) + cos(x)*sin(x) ⇒ sin(2x) = 2sin(x)cos(x)

From eq. 2

If x = y

cos ( x + x ) = cos(x)*cos(x) - sin(x)*sin(x)  ⇒ cos²(x) - sin²(x)

cos (2x) = cos²(x) - sin²(x)

Hence:The expression:

cos(2x) cos(x) + sin(2x) sin(x)  (3)

Subtition of sin(2x) and cos(2x)  in eq. 3

[cos²(x)-sin²(x)]*cos(x) + [(2sen(x)cos(x)]*sin(x)

and operating

cos³(x) - sin²(x)cos(x) + 2sin²(x)cos(x) = cos³(x) + sin²(x)cos(x)

cos (x) [ cos²(x) + sin²(x) ]  = cos(x)

since cos²(x) + sin²(x) = 1

8 0
3 years ago
On factorising 14pq + 35pqr. we get?
Anna71 [15]

Answer:

7pq( 2 + 5r)

Step-by-step explanation:

4 0
3 years ago
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