All categories

4 years ago

Simplify 3^2 times 3^3!!! i need help

Mathematics

1 answer:

zvonat [6]4 years ago

8 0

Here's a property of exponents.

$a^b \times a^c = a^{b+c}$

We have to simplify $3^2 \times 3^3$
Use the property of exponents I have shown.

$3^2 \times 3^2}=3^{2+3}=3^5$

You chose the right answer. Good job! Hope this helps! :)

You might be interested in

2а + 20 = -3а - 5 pls help

sammy [17]

Answer: A= -5

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

How many times does six go into 48

WINSTONCH [101]

8 times
6x6 equals 36 so add 12 to get 48
12=6x2

8 0

4 years ago

Read 2 more answers

find the x-intercept of the parabola with vertex (4,-1) and y- intercept (0,15). write answer in (x1,y1) (x2,y2) form :D ...?

Vaselesa [24]

Vertex form of the equation:
y = a ( x - h )² + k;
15 = a ( 0 - 4 )² - 1
15 = 16 a - 1
16 a = 16
a = 16 : 16
a = 1
After that we have to transform the equation to the standard form:
y = ( x - 4 )² - 1
y = x² - 8 x + 16 - 1
y = x² - 8 x + 15
Finally we have to find the zeroes:
x² - 8 x + 15 = 0
x² - 5 x - 3 x + 15 = 0
x ( x - 5 ) - 3 ( x - 5 ) = 0
( x - 5 ) ( x - 3 ) = 0
x = 3, x = 5
Answer:
( x 1, y 1 ) ; ( x 2 , y 2 ) = ( 3, 0 ) ; ( 5 , 0 )

3 0

3 years ago

Is this congruent by SSS, SAS, AAS, ASA? Pls lemme know! Only if you know though

Mashcka [7]

9514 1404 393

Answer:

SSS

Step-by-step explanation:

Two sides are marked congruent and the third side is shared. It is congruent to itself.

Hence, all three sides are congruent, and you can invoke the SSS congruence postulate to say the triangles are congruent.

7 0

3 years ago

Read 2 more answers

Which elementary row operation will reduce the x–element in row 2 to 0 in this matrix?

AysviL [449]

The elementary row operation that will reduce the x–element in row 2 to 0 in this matrix is -2R1 + R2

<h3>How to determine the elementary row operation?</h3>

The complete question is added as an attachment

The matrix is given as:

1 1 1 12

2 1 0 14

2 0 3 19

Rewrite as:

x y z

1 1 1 12

2 1 0 14

2 0 3 19

So, the x-element of the second row is

x = 2

When the first row is multiplied by negative 2 and added to the second row, the x-element of the second row is reduced to 0

This is represented as;

-2R1 + R2

i.e.

-2(1 1 1 12)

+ 2 1 0 14

---------------------------

0 -1 -2 -10

Hence, the elementary row operation that will reduce the x–element in row 2 to 0 in this matrix is -2R1 + R2