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Paula tossed the football over the fence.
Answer: at the equator the normal force will be 3.4N less and at the North Pole = 980N
Explanation:
So, we will start the Calculation by considering the equation below;
Fnet = F(g) - F(N); where Fnet = mv^2/ r.
Hence, F(g) - F(N) = mv^2/ r -------------(1).
Making F(N) the subject of the formula, we have;
F(N) = Gm1m2/r^2 - mv^2/r.
Thus, we have;
Gm1m2/r^2 = 6.68 × 10^-11 × (5.98 × 20^24) × 100/ 6.38 × 10^6 = 980N.
Also, we have;
mv^2/r = m4π^2r/T^2.
100 × 6.38 ×10^6 × 4π^2/(24 × 3600)^2 = 3.4N
Therefore, at the equator the normal force will be 3.4N less and at the North Pole = 980N.
Answer:
During high tide when the level of seawater rises, more sea water is brought into the estuary. This makes the water very salty and thus increases the percentage of dissolved salt in the estuary. Therefore, at high tide, the salinity of an estuary increases significantly.
Explanation:
Answer:
A≈907.92in²
Explanation:
A=πr2=π·172≈907.92028in² hope this helps ;)