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KatRina [158]
3 years ago
5

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards. If the actual width of a neighborhood park is 62 yard

s, how wide is the park in drawing?
Mathematics
1 answer:
klemol [59]3 years ago
8 0

Answer:

The park is <u>31 inches</u> wide in the drawing.

Step-by-step explanation:

Given:

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.

The actual width of a neighborhood park is 62 yards.

Now, to find the width of park in drawing.

Let the width of park in drawing be x.

The scale drawing of the city is 1 inch : 2 yards.

So, 1 inch is equivalent to 2 yards.

Thus, x is equivalent to 62 yards.

Now, to get the width of park in drawing by using cross multiplication method:

\frac{1}{2} =\frac{x}{62}

By cross multiplying we get:

62=2x

Dividing both sides by 2 we get:

31=x

x=31\ inches.

Therefore, the park is 31 inches wide in the drawing.

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Step-by-step explanation:

5 0
4 years ago
A friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work
lubasha [3.4K]

Answer:

The probability that he drove the small car is 0.318.

Step-by-step explanation:

We are given that a friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car.

If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5.

Let the Probability that he drives the small car = P(S) = \frac{1}{4} = 0.25

Probability that he drives the large car = P(L) = \frac{3}{4} = 0.75

Also, let WT = event that he is at work on time

So, Probability that he is at work on time given that he takes the small car = P(WT / S) = 0.7

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Now, given that he was at work on time on a particular morning, the probability that he drove the small car is given by = P(S / WT)

We will use the concept of Bayes' Theorem for calculating above probability;

So,    P(S / WT)  =  \frac{P(S) \times P(WT/S)}{P(S) \times P(WT/S)+P(L) \times P(WT/L)}

                          =  \frac{0.25 \times 0.7}{0.25 \times 0.7+0.75 \times 0.5}

                          =  \frac{0.175}{0.55}

                          =  <u>0.318</u>

Hence, the required probability is 0.318.

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Answer:

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Step-by-step explanation:

A proportional relationship is a relationship where the ordered pairs are the same. 2 and 2 are the same.

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