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KatRina [158]
3 years ago
5

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards. If the actual width of a neighborhood park is 62 yard

s, how wide is the park in drawing?
Mathematics
1 answer:
klemol [59]3 years ago
8 0

Answer:

The park is <u>31 inches</u> wide in the drawing.

Step-by-step explanation:

Given:

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.

The actual width of a neighborhood park is 62 yards.

Now, to find the width of park in drawing.

Let the width of park in drawing be x.

The scale drawing of the city is 1 inch : 2 yards.

So, 1 inch is equivalent to 2 yards.

Thus, x is equivalent to 62 yards.

Now, to get the width of park in drawing by using cross multiplication method:

\frac{1}{2} =\frac{x}{62}

By cross multiplying we get:

62=2x

Dividing both sides by 2 we get:

31=x

x=31\ inches.

Therefore, the park is 31 inches wide in the drawing.

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Step-by-step explanation:

To find volume, multiply the numbers by length, width, and height.

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Answer:

See Below.

Step-by-step explanation:

We are given the isosceles triangle ΔABC. By the definition of isosceles triangles, this means that ∠ABC = ∠ACB.

Segments BO and CO bisects ∠ABC and ∠ACB.

And we want to prove that ΔBOC is an isosceles triangle.

Since BO and CO are the angle bisectors of ∠ABC and ∠ACB, respectively, it means that ∠ABO = ∠CBO and ∠ACO = ∠BCO.

And since ∠ABC = ∠ACB, this implies that:

∠ABO = ∠CBO =∠ACO = ∠BCO.

This is shown in the figure as each angle having only one tick mark, meaning that they are congruent.

So, we know that:

\angle ABC=\angle ACB

∠ABC is the sum of the angles ∠ABO and ∠CBO. Likewise, ∠ACB is the sum of the angles ∠ACO and ∠BCO. Hence:

\angle ABO+\angle CBO =\angle ACO+\angle BCO

Since ∠ABO =∠ACO, by substitution:

\angle ABO+\angle CBO =\angle ABO+\angle BCO

Subtracting ∠ABO from both sides produces:

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The two non-parallel sides of an isosceles trapezoid are each 7 feet long. The longer of the two bases measures 22 feet long. Th
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<h3>How to determine the length</h3>

The cosine rule is given as;

c = \sqrt{a^2 + b^2 - 2ab cos \alpha }

c = length of the diagonal

a = base length = 22 feet

b = 7 feet

c = \sqrt{7^2 + 22^2 - 2 * 7 * 22 cos 40}

c = \sqrt{533 - 308 * 0. 7660}

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c = \sqrt{297. 072}

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Using sine rule

\frac{a}{sin A }  = \frac{c}{sin C}

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a × 0. 8660 = 17. 24 × 0. 9397

a = \frac{16. 20}{0. 8660}

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Learn more about  isosceles trapezoid here:

brainly.com/question/10187910

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Given a rectangular prism of dimension W, L, and H, the volume is calculated as:

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D: V = 6*2*3 = 36 cube cm

E: V = 2*4*2 = 16 cube cm

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