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lbvjy [14]
3 years ago
6

Help me please! which bisects the chord?

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

B. 3

Step-by-step explanation:

Since you are given that chord AB's length is 8 and is bisected by segment XC, that means segment BC's length is 4 and ∠XCB is a right angle. From there, we use Pythagorean Theorem to solve for length XC:

4² + b² = 5² (Or remember 3-4-5 makes a Pythagorean triple)

c = √(5²-4²)

c = 3

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amm1812

Answer:

If the equation is in the form, ax + b = c, where x is the variable, you can solve the equation as before. First “undo” the addition and subtraction, and then “undo” the multiplication and division. Solve 3y + 2 = 11. Subtract 2 from both sides of the equation to get the term with the variable by itself.

Hope this helps :D

7 0
3 years ago
H(x)=17+ x/6<br> find x.<br> i will give brainliest 100 points
pickupchik [31]

Answer:

x = -11

Step-by-step explanation:

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4 years ago
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Yesterday it took 40 minutes to drive to school. Today is took 32 minutes to drive to
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Answer:

20%

Step-by-step explanation:

To find the percent decrease, we do old number subtracted from the new numbers over old.

We do

40 - 32 = 8

Then we put the 8 over the old and get

8/40

In percentage form it would be 20%

8 0
3 years ago
If Grayson has filled 4 more sketchbooks with drawings at home than he has filled at school, how many sketchbooks has he filled
salantis [7]

Answer:

2x + 4

Step-by-step explanation:

I'm guessing there are no exact numbers

home = x + 4

school = x

x + x + 4

2x + 4

8 0
3 years ago
To calculate the cost of painting his silo, a farmer must find its height. The farmer uses a cardboard square to line up the top
musickatia [10]

Answer:

Height of the silo = 18 feet.

Step-by-step explanation:

From the figure attached BC is the length of the silo and the height of the farmer is 5 ft.

Farmer is standing at 8 ft distance from the silo.

From triangle AEC,

tan(∠CAE) = CE/AE=5/8

m(∠CAE) = tan-1 (5/8)

= 32°

m∠BAE = 90° - 32° = 58°

From the triangle ABE,

tan58° = BE/AE

BE = 8tan58°

BE = 12.8 ft

Total height of the silo = BE + EC

= 12.8 + 5

= 17.8

≈ 18 ft          

Therefore, the total height of the silo is 18 ft.

6 0
3 years ago
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