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2 years ago

6

Help me please! which bisects the chord?

1 answer:

8_murik_8 [283]2 years ago

6 0

Answer:

B. 3

Step-by-step explanation:

Since you are given that chord AB's length is 8 and is bisected by segment XC, that means segment BC's length is 4 and ∠XCB is a right angle. From there, we use Pythagorean Theorem to solve for length XC:

4² + b² = 5² (Or remember 3-4-5 makes a Pythagorean triple)

c = √(5²-4²)

c = 3

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A multiple-choice standard test contains total of 25 questions, each with four answers. Assume that a student just guesses on ea

weqwewe [10]

Answer:

a) 8*88*10⁻⁶ ( 0.00088 %)

b) 0.2137 (21.37%)

Step-by-step explanation:

if the test contains 25 questions and each questions is independent of the others, then the random variable X= answer "x" questions correctly , has a binomial probability distribution. Then

P(X=x)= n!/((n-x)!*x!)*p^x*(1-p)^(n-x)

where

n= total number of questions= 25

p= probability of getting a question right = 1/4

then

a) P(x=n) = p^n = (1/4)²⁵ = 8*88*10⁻⁶ ( 0.00088 %)

b) P(x<5)= F(5)

where F(x) is the cumulative binomial probability distribution- Then from tables

P(x<5)= F(5)= 0.2137 (21.37%)

7 0

2 years ago

HELP ILL AWARD BRAINLIEST

Leokris [45]

Answer:

7. 10 8. 20 9. 100 thats all i know

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The manufacturer offers a $125 rebate on photocopiers purchases before january 1. what is the nest cost of a $1,475 photocopier

Yuri [45]

Answer:

The net cost of the photocopier before january 1 is <u>$1350.</u>

Step-by-step explanation:

Given:

The manufacturer offers a $125 rebate on photocopiers purchases before january 1.

Now, to find the net cost of $1,475 photocopier before january 1.

Amount of rebate before January 1 = $125.

Cost of photocopier = $1,475.

So, to get the net cost of $1475 photocopier before january 1 we subtract the rebate from it:

$\$1475-\$125$

$=\$1350.$

Therefore, the net cost of the photocopier before january 1 is $1350.

6 0

2 years ago

a driver is below the surface of the water at - 15m. he dives down by 6m, then rises 4m where is he now

nevsk [136]

Given:

A driver is below the surface of the water at - 15m. he dives down by 6m, then rises 4m.

To find:

The current location of the driver.

Solution:

In this problem, negative sign is used for downward direction or the distance below the surface of the water.

Initial location = -15 m

Dives down by 6m, it means - 6m, then rises 4m, it means 4 m.

Now, the current location is

$-15 m-6m+4m$

$=-21m+4m$

$=-17m$

Therefore, the correct location of the driver is at -17 m it means her is 17 m below the surface of the water.

6 0

2 years ago

What are the solution(s) to the quadratic equation 50 – x2 = 0?

Dmitrij [34]

Answer:

x = ± $5\sqrt{2}$

Step-by-step explanation:

We have been given the quadratic equation;

$50-x^{2}=0$

The first step is to subtract 50 from both sides of the equation;

$50-x^{2}-50=0-50$

$-x^{2}=-50$

Multiplying both sides by -1 yields;

$x^{2}=50$

The final step is to obtain square roots on both sides;

$\sqrt{x^{2} }=\sqrt{50}\\x=+/-\sqrt{50}$

Therefore, x = ± $5\sqrt{2}$

5 0

2 years ago