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irga5000 [103]
3 years ago
13

ΔXYZ ≅ΔFED where m∠X = 50°, m∠Y=30°, m∠D=2y+10, XY =9 and EF=3x−12. Solve for x and y.

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

The value of x is 7 and value of y is 45

Step-by-step explanation:

In ΔXYZ

∠X = 50°, ∠Y=30°

To Find ∠Z we will use angle sum property of triangle (Sum of all angles of triangles is 180°)

So,∠X + ∠Y + ∠Z = 180°

So,50°+30°+ ∠Z = 180°

∠Z=180°-80°

∠Z=100°

Now we are given that ΔXYZ ≅ΔFED

So, the corresponding sides are equal and the corresponding angles are equal.

So, ∠Z= ∠D

So, 100=2y+10

100-10=2y

90=2y

45=y

Now XY = EF

So, 9 = 3x-12

21=3x

7=x

Hence The value of x is 7 and value of y is 45

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Step-by-step explanation:

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barxatty [35]

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By the chain rule, we have

\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}

and

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Then

\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)

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Step-by-step explanation:

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