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3 years ago

Choose the product as a base with an exponent

Mathematics

1 answer:

iren2701 [21]3 years ago

8 0

I’m not sure why I don’t feel good at this time I just want you in my head I don’t want you in my

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Solve the above questions don't spam

Bas_tet [7]

Answer:

10th question ka answer hai OK

7 0

3 years ago

The number of pies sold by the Chipper Bakery is 3/4 of the number of cookies sold by the Yummy Cookie Company. If both the busi

Mariulka [41]

Answer:

Number of cookies sold by the Yummy Company = 32.

Step-by-step explanation:

Let the number of cookies sold by the yummy company be x.

Then the number of pies sold by The Chipper Bakery is 3/4 x.

When they have 16, more we have:

Number sold by the Yummy company is x + 16 and the number sold by the Bakery is 5/6 (x + 16)

So x + 3/4x + 2(16) = x + 16 + 5/6(x + 16)

= 7/4 x + 32 = 11/6 x + 16 + 80/6

7/4 x - 11/6x = 16 + 80/6 - 32

-1/12 x = -2 2/3

x = -8/3 * -12

x = 32.

5 0

3 years ago

What is the vertex on a right angle

Pachacha [2.7K]

The vertex would be the point on the right angle like the tip of the right angle

6 0

2 years ago

What is the equation, in standard form, of a parabola that models the values in the table?

love history [14]

Answer:

$Y=4x^2+3x-6$

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

$Y=3x^2+4x-6$ for (-2,4)

$Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\$

This does not give 4 as the answer and is not a solution.

$Y=4x^2+3x-6$ for (-2,4)

$Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\$

This does give 4 as the answer and is a possible solution.

$Y=4x^2-3x-6$ for (-2,4)

$Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\$

This does not give 4 as the answer and is not a solution.

$Y=-4x^2-3x-6$ for (-2,4)

$Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\$

This does not give 4 as the answer and is not a solution.

The only possible solution is $Y=4x^2+3x-6$

3 0

3 years ago

A total of $5000 is invested: part at 9% and the remainder at 14%. How much is invested at each rate if the annual interest is $

IceJOKER [234]

9514 1404 393

Answer:

$200 at 14%
$4800 at 9%

Step-by-step explanation:

Let x represent the amount invested at 14%. Then 5000-x is the amount invested at 9%. The interest earned is ...

(14%)x +(9%)(5000 -x) = 460

0.05x +450 = 460 . . . . . . . . . . simplify

0.05x = 10 . . . . . . . . . . . . . . subtract 450

x = 200 . . . . . . . . . . . . . . divide by 0.05

5000-x = 5000-200 = 4800

$200 was invested at 14%; $4800 was invested at 9%.

7 0

2 years ago