All categories

3 years ago

Which expression is a difference of cubes? O X6-6 O X6-8 O x8-6 O x8-8

Mathematics

2 answers:

Feliz [49]3 years ago

7 0

Answer:

x6 - 8

Step-by-step explanation:

UkoKoshka [18]3 years ago

4 0

Answer:

$x^{6}$ - 8

Step-by-step explanation:

A difference of cubes has the form

a³ - b³

Note that $x^{6}$ is a perfect cube, that is $(x^2)^{3}$ , but

$x^{8}$ is not

8 is a perfect cube, that is 2³ , but 6 is not

Thus

$x^{6}$ - 8 ← is a difference of cubes

= $(x^2)^{3}$ - 2³

You might be interested in

The cube root of 0.000004913 is

Vlad1618 [11]

Answer:

$\sqrt[3]{0.000004913}=0.017$

Step-by-step explanation:

<u>Cubic Root </u>

The cubic root of a number N is M, if

$M^3=N$

It's usually tedious to manually compute cubic roots, but if we use some basic algebra concepts, the job is easily done.

Let's compute

$M=\sqrt[3]{0.000004913}$

The argument can be expressed in scientific notation as

$0.000004913= 4913\ 10^{-9}$

The power of 10 has an exact cubic root since the exponent is a multiple of 3. To find the cubic root of the mantissa, we note it's the triple product of 17, i.e.

$4913=17*17*17=17^3$

Thus our number is

$M=\sqrt[3]{17^3\ 10^{-9}}=17\ 10^{-3}=0.017$

We have then

$\boxed{\sqrt[3]{0.000004913}=0.017}$

4 0

4 years ago

Find the 93rd term of the arithmetic sequence -11, -7, -3

alina1380 [7]

Answer:

357

Step-by-step explanation:

hello :

note : the n th term of an arithmetic sequence is :

An =A1+(n-1)d ....a common difference is : d and A1 the first term

in this exercice : d = -3-(-7) =-7-(-11) = 4 A1 = -11

when : n =93 you have the 93rd term A93

so : A93 = -11 +(93-1)(4)

A93 = 357

7 0

3 years ago

Kiki is taking a bicycle ride. During the ride, Kiki is always traveling away from the starting point. Wich of the following gra

inysia [295]

I'm 100% sure that the answer is C

5 0

4 years ago

List five bias questions.

ki77a [65]

Go to Calvin. Edu hope this helps.

4 0

3 years ago

The cost of a daily newspaper varies from city to city. However, the variation among prices remains steady with a population sta

vekshin1

Answer:

Yes, there is sufficient evidence to support the claim that the mean cost is $1.

Step-by-step explanation:

Data Given:

The population standard deviation $\sigma$ = $0.2

The sample mean cost $\bar {X}$ = $0.93

The sample size n = 12

From above we can use the Z-test for testing the mean from the above given data.

To check whether the mean cost of newspaper is $1.00

$\mathbf{H_o}$ : $\mu$ = $1

$\mathbf{H_1}$ : $\mu$ $\neq$ $1

The test statistics Z = $\frac{\bar {X}- \mu}{\frac{\sigma }{\sqrt{n}} }$

Z = $\frac{0.93- 1}{\frac{0.2}{\sqrt{12}} }$

Z = -1.212

The P-value = 2P (Z< - 1.212)

= 2 × 0.1128

= 0.2256

Since the value of P is more than the significance level; do not reject the $\mathbf{H_o}$

Conclusion: We therefore conclude that there is sufficient evidence to support the claim that the mean cost is $1.

8 0

3 years ago