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sattari [20]
3 years ago
12

Which expression is a difference of cubes? O X6-6 O X6-8 O x8-6 O x8-8

Mathematics
2 answers:
Feliz [49]3 years ago
7 0

Answer:

x6 - 8

Step-by-step explanation:

UkoKoshka [18]3 years ago
4 0

Answer:

x^{6} - 8

Step-by-step explanation:

A difference of cubes has the form

a³ - b³

Note that x^{6} is a perfect cube, that is (x^2)^{3}, but

x^{8} is not

8 is a perfect cube, that is 2³ , but 6 is not

Thus

x^{6} - 8 ← is a difference of cubes

= (x^2)^{3} - 2³

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The cube root of 0.000004913 is
Vlad1618 [11]

Answer:

\sqrt[3]{0.000004913}=0.017

Step-by-step explanation:

<u>Cubic Root </u>

The cubic root of a number N is M, if

M^3=N

It's usually tedious to manually compute cubic roots, but if we use some basic algebra concepts, the job is easily done.

Let's compute

M=\sqrt[3]{0.000004913}

The argument can be expressed in scientific notation as

0.000004913= 4913\ 10^{-9}

The power of 10 has an exact cubic root since the exponent is a multiple of 3. To find the cubic root of the mantissa, we note it's the triple product of 17, i.e.

4913=17*17*17=17^3

Thus our number is

M=\sqrt[3]{17^3\ 10^{-9}}=17\ 10^{-3}=0.017

We have then

\boxed{\sqrt[3]{0.000004913}=0.017}

4 0
4 years ago
Find the 93rd term of the arithmetic sequence -11, -7, -3
alina1380 [7]

Answer:

357

Step-by-step explanation:

hello :

note :    the n th term of an arithmetic sequence is :

An =A1+(n-1)d   ....a common difference is : d  and A1 the first term

in this exercice :   d = -3-(-7) =-7-(-11) = 4        A1 =  -11

when : n =93 you have the  93rd term  A93

so : A93 = -11 +(93-1)(4)

A93 = 357

7 0
3 years ago
Kiki is taking a bicycle ride. During the ride, Kiki is always traveling away from the starting point. Wich of the following gra
inysia [295]
I'm 100% sure that the answer is C
5 0
4 years ago
List five bias questions.
ki77a [65]
Go to Calvin. Edu hope this helps.
4 0
3 years ago
The cost of a daily newspaper varies from city to city. However, the variation among prices remains steady with a population sta
vekshin1

Answer:

Yes, there is sufficient evidence to support the claim that the mean cost is  $1.

Step-by-step explanation:

Data Given:

The population standard deviation \sigma = $0.2

The sample mean cost \bar {X} = $0.93

The sample size n = 12

From above we can use the Z-test for testing the mean from the above given data.

To check whether the mean cost of newspaper is $1.00

\mathbf{H_o} : \mu = $1

\mathbf{H_1} : \mu  \neq $1

The test statistics Z = \frac{\bar {X}- \mu}{\frac{\sigma }{\sqrt{n}} }

Z = \frac{0.93- 1}{\frac{0.2}{\sqrt{12}} }

Z = -1.212

The P-value = 2P (Z< - 1.212)

= 2 × 0.1128

= 0.2256

Since the value of P is more than the significance level; do not reject the \mathbf{H_o}

Conclusion: We therefore conclude that there is sufficient evidence to support the claim that the mean cost is  $1.

8 0
3 years ago
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