Answer:
The 95% confidence interval for the measurements is [48.106, 53.494].
Step-by-step explanation:
The average M of this sample is

The standard deviation s of this sample is

![s=\sqrt{\dfrac{1}{4}\cdot [(52-50.8)^2+(48-50.8)^2+(49-50.8)^2+(52-50.8)^2+(53-50.8)^2]}](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20%5B%2852-50.8%29%5E2%2B%2848-50.8%29%5E2%2B%2849-50.8%29%5E2%2B%2852-50.8%29%5E2%2B%2853-50.8%29%5E2%5D%7D)
![s=\sqrt{\dfrac{1}{4}\cdot [(1.44)+(7.84)+(3.24)+(1.44)+(4.84)]}=\sqrt{\dfrac{18.8}{4}}=\sqrt{4.7}\\\\\\s=2.168](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20%5B%281.44%29%2B%287.84%29%2B%283.24%29%2B%281.44%29%2B%284.84%29%5D%7D%3D%5Csqrt%7B%5Cdfrac%7B18.8%7D%7B4%7D%7D%3D%5Csqrt%7B4.7%7D%5C%5C%5C%5C%5C%5Cs%3D2.168)
The degrees of freedom are

Then, the critical value of t for a 95% CI and 4 degrees of freedom is t=2.776.
The margin of error of the CI is:

Then, the lower and upper bounds of the CI are:

The 95% confidence interval for the measurements is [48.106, 53.494].
Answer:
I don't think devlance is a real word but maybe u r trying to sat deviance The answer might be B
Step-by-step explanation:
(199-55)/9= t
Let t equal the number of hours you have to work
Answer:
If 4 fish are randomly selected, what is the probability that the mean weight will be between 9.6 and 15.6 lb? Round your answer to four decimal places.
The product of 14560 and 10 is 145600