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Inessa05 [86]
3 years ago
7

HELP! PLEASE! Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25

times the width of the section.
Part A
Create an equation to represent the area of the basketball section, A, in terms of the width, w.
Part B
Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?
SHOW ALL WORK PLEASE
Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer:

Part A) A=1.25W^2

Part B) Length: 17.5 feet and Width: 14 feet

Step-by-step explanation:

Part A) Create an equation to represent the area of the basketball section A, in terms of the width W.

Let

L ----> the length of the  rectangular basketball section

W ---> the width of the  rectangular basketball section

we know that

The area of the rectangular basketball section is equal to

A=LW ----> equation A

The length of the section will be 1.25 times the width of the section

so

L=1.25W ----> equation B

substitute equation B in equation A

A=(1.25W)W\\A=1.25W^2

Part B) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?

we have

A=1.25W^2\\A=245\ ft^2

so

245=1.25W^2

solve for W

W^2=245/1.25\\W^2=196\\W=14\ ft

Find the value of L

substitute the value of W in the equation B

L=1.25(14)=17.5\ ft

therefore

The dimensions are :

Length: 17.5 feet

Width: 14 feet

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