Let time be t , distance be d
Put value in eq(2)
Answer:
a. (2x - 3)(x - 4)
b. 17 m, 6 m
c. 46 m
Step-by-step explanation:
a.
2x² - 11x + 12 = (2x - 3)(x - 4)
b.
2x - 3 = 2(10) - 3 = 17
x - 4 = 10 - 4 = 6
c.
P = 2L + 2W = 2(17) + 2(6) = 46
Answer:
Step-by-step explanation:
9) (25-x^2 )(a+2) = (5-x)(5+x)(a+2)
11) 9(v-3)+u^2(3-v)
9(v-3)+u^2( -v+3)
9(v-3)-u^2( v-3)
(9-u^2)(v-3)
(3-u)(3+u)(v-3)
secx=1/cosx
1. To solve this problem you must apply the following proccedure:
2. You have to verify if secx sinx=tanx, so, you have:
3. You know that secx=1/cosx, and tanx=sinx/cosx, therefore:
(secx)(sinx)
(1/cosx)(sinx)
sinx/cosx
tanx
Answer:
-3c^8
Step-by-step explanation:
