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zlopas [31]
3 years ago
10

The function f(x) is a cubic function and the zeros of f(x) are -3, -2, and 1. The y-intercept of f(x) is -24. Write the equatio

n of the cubic polynomial in standard form.
Mathematics
1 answer:
Serga [27]3 years ago
7 0

Answer:

f(x) = 4x³+16x²+4x-24

Step-by-step explanation:

Factors are (x+3)(x+2)(x-1)

(x+3)(x²+2x-x-2)

(x+3)(x²+x-2)

x³+x²-2x+3x²+3x-6

x³+4x²+x-6

This could have been the function but the intetcept is 6 here.

So we'll take a miltiple of this one such that the intercept becomes-24

-24/-6 = 4

That multiple is 4

f(x) = 4(x³+4x²+x-6)

f(x) = 4x³+16x²+4x-24

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<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>

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<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>

<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>

<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
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<span>Solving with the Quadratic Formula gives: </span>

<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>

<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>

<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>

<span>I hope this helps! ^^ Brainliest Please?</span><span>
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X = 37.6 I believe. Am I correct or no?​
I am Lyosha [343]
I believe you are correct
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