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Answer:
a. One of the chocolate candies weighed 0.776 gram and it was heavier than 25 of the other chocolate candies. What is the percentile of this particular value?
It is the <u>5</u>th percentile.
b. One of the chocolate candies weighed 0.876 gram and it was heavier than 329 of the other chocolate candies. What is the percentile of this particular value?
It is the <u>71</u>th percentile.
c. One of the chocolate candies weighed 0.856 gram and it was heavier than 229 of the other chocolate candies. What is the percentile of this particular value?
It is the <u>49</u>th percentile.
Step-by-step explanation:
So when we are talking about percentile, what it means is the point below a certain score or percentage lies, or the rank.
The formula is simple:
Let's call percentile pth, pth=
where p is the position in the data set you want to evaluate (in statistical analysis, these are called quartiles, and they are useful for evaluating groups, so 3 quartiles would divide sample into 25th, 50th and 75th, four quartiles would be 20th, 40th, 60th, 80th, and so on).
and n is the number of elements in the set
For this problem there are no quartiles specified, but we can then work with the definition of percentile, meaning, if you are the 5th percentile, then 95% of the group are above you.
a. So 0.776 was heavier than 25 others, meaning it is in the 26th position out of 463. But we need that in relation to 100, so is 0.0562 or about 5/100, (rounded down). That would mean that the percentile is:
pth=*100=5.62 or 5, rounded down
b. 0.876 was heavier than 329 others, meaning it is in the 330th position out of 463. In relation to 100, so is 0.7127 or about 71/100, (rounded down). That would mean that the percentile is:
pth=*100=71.27 or 71, rounded down
c. 0.856 was heavier than 229 others, meaning it is in the 230th position out of 463. In relation to 100, so is 0.4967 or about 49/100, (rounded down). That would mean that the percentile is:
pth=*100=49.67 or 49, rounded down
Answer:
4th statement is true.
Step-by-step explanation:
We have been two box plots, which represents the number of calories in each snack pack of crackers and cookies. We are asked to find the correct statement about our given box plots.
1. More packets of crackers have 80 calories than any other number of calories.
We can see that median of box plot representing calories of cookies is 80. This means that half of the packets of crackers have less than 80 calories and half of the packets have more than 80 calories, therefore, 1st statement is false.
2. The value 70 is an outlier for the number of calories in the cookie pack.
Since an outlier is 1.5 times the interquartile range.
Since any number less than 67.5 will be an outlier and 70 is grater than 67.5, therefore, 70 is not an outlier in number of calories in cookie packs and 2nd statement is false.
3. The upper quartile of the cookie data is equivalent to the maximum in the cracker data.
We can see that upper quartile of cookie data is 105 and the maximum in cracker data is 100. Since 105 is greater than 100, therefore, 3rd statement is false.
4. The number of calories in each pack of cookies has a greater variation than the number of calories in each pack of crackers.
Since range and IQR are good measures of variation of box-plots, so we will find the range and IQR of our both box-plots.
We have already seen that IQR of cookie packs is 15.
We can see that the range of calories in cookie packs (45) is greater than range of calories in cracker packs (30) and IQR of calories in cookie packs (15) is greater than IQR of calories in cracker packs (10), therefore, 4th statement is true.
The general form of such an equation will be
where
A = amplitude (3)
B = horizontal shift to the right (-π)
C = period (4π)
D = vertical offset (0)
Your equation will be ...
where
A = amplitude (3)
B = horizontal shift to the right (-π)
C = period (4π)
D = vertical offset (0)
Your equation will be ...