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djverab [1.8K]
3 years ago
15

What similarity property, if any, can be used to show that the following two triangles are similar.

Mathematics
2 answers:
Reil [10]3 years ago
6 0
They both have right angles and have the same angles overall. Essentially they are the same size, one is just expanded bigger than the other. It might be dilation. The inside line so indicate the similarity in angle sizes.
PtichkaEL [24]3 years ago
3 0

Answer:

The angles

Step-by-step explanation:

On both triangles, there is a square in the corner which means that both angles are 90 degrees, and then on the left side of the triangle, there are two signs that are the sames meaning those two have the same angle measurement. Based on this knowledge I know that the last angle of the triangle must also be the same degrees since both triangles follow the same equation 90+a+b=180. I know that all angle measurements from one triangle must equal 180. So these are the same triangles with different sizes.

Hope this helps you

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Liam works in a toy store that sells bags of marbles. he put 10 marbles in each bag and 2/10 of the marbles are striped. if Liam
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"A cylindrical container has a radius of 25 inches and a height of 31 inches. What is the volume of
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Use the formula:

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Step-by-step explanation:

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3 years ago
Break apart 35 into 30+5=
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The sides of a triangle are x , x +1 , 2 x -1 and its area is x root of 10 .Find the value of x.
VARVARA [1.3K]


Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.

Substitute the known values into the formula:

x√10=√{[(x+x+1+2x-1)/2][({x+x+1+2x-1}/2)-x][({x+x+1+2x-1}/2)-(x+1)][({x+x+1+2x-1}/2)-(2x-1)]}

Simplify:

<span>x√10=√{[4x/2][(4x/2)-x][(4x/2)-(x+1)][(4x/2)-(2x-1)]}</span>

<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>

<span>x√10=√[2x(x)(x-1)(1)]</span>

<span>x√10=√[2x²(x-1)]</span>

<span>x√10=√(2x³-2x²)</span>

<span>10x²=2x³-2x²</span>

<span>2x³-12x²=0</span>

<span>2x²(x-6)=0</span>

<span>2x²=0 or x-6=0</span>

<span>x=0 or x=6</span>

<span>Therefore, x=6 (you can't have a length of 0).</span>

6 0
3 years ago
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