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djyliett [7]
3 years ago
13

Round 85,001 to the nearest ten thousand

Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0

the answer is 90,000

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Please hurry. it's geometry.
Ainat [17]

That would be option A as the angles  and sides  ( the AS) have already been stated.

7 0
3 years ago
Find the area and perimeter.
DanielleElmas [232]

Step-by-step explanation:

Perimeter = 12 + x + 6 + 2x + 5

Perimeter = 3x + 23.

Area = ½ × b × h

Area = ½ × 12 × (x + 6)

Area = 6(x + 6)

Area = 6x + 36

4 0
3 years ago
A square is cut from a rectangle. The side length of the square is half of the unknown width w. The area of the shaded region is
Virty [35]

Answer:

  • See below

Step-by-step explanation:

<u>The side of the square is w/2, then its area is:</u>

  • A = (w/2)² = w²/4

<u>The shaded area is the difference of areas of the rectangle and the square:</u>

  • 14w - w²/4 = 84

<u>This can be simplified:</u>

  • 56w - w² = 336
  • w² - 56w + 336 = 0

8 0
2 years ago
What is 35 cents times 500 ​
kvasek [131]

Answer:

17500

Step-by-step explanation:

you just multiply it by 35 if it is pennies but you have to tell me if it is dimes or whatever

7 0
3 years ago
Read 2 more answers
If a cup of coffee has temperature 97°C in a room where the ambient air temperature is 25°C, then, according to Newton's Law o
FinnZ [79.3K]

Answer:

The  average temperature  is T_{a} = 81.95^oC

Step-by-step explanation:

From the question we are told that

    The temperature of the coffee after time t is   T(t) =  25 + 72 e^{[-\frac{t}{45} ]}

Now the average temperature during the first 22 minutes i.e fro 0 \to  22minutes is mathematically evaluated as

              T_{a} =  \frac{1}{22-0}  \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx

               T_{a} = \frac{1}{22} [25 t  +  72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.

             T_{a} = \frac{1}{22} [25 t  - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.

              T_{a} = \frac{1}{22} [25 (22)  - 3240e^{[-\frac{22}{45} ]}   - (- 3240e^{0} )]

            T_{a} = \frac{1}{22} [550  - 1987.12  +  3240]

          T_{a} = 81.95^oC

       

8 0
3 years ago
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