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Aliun [14]
3 years ago
7

Right triangle ABC is isosceles and point M is the midpoint of the hypotenuse.

Mathematics
2 answers:
kotykmax [81]3 years ago
8 0

Answer:

Step-by-step explanation:

I need this to ekk

SSSSS [86.1K]3 years ago
7 0

Answer:

I just did that one, it's C - isosceles right triangle.

Step-by-step explanation:

hopes this helps

You might be interested in
Evaluate the expression below when x = 9 and y = 12. <br> 4(x + 6) - 3(y + 4)
Viefleur [7K]
The answer would be 12
8 0
3 years ago
One number is 6 more than twice another. If their sum is 51, find the numbers.
joja [24]

Answer:

y=2x+6 ; x+y=51

Step-by-step explanation:

assuming x is one number and y is the other -

one number (y) is 6 more (+6) than twice another (2x) -

using that knowledge we form an equation -

y=2x+6

the sum (x+y) is 51

using this knowledge we can make the equation -

x+y=51

now you have -

y=2x+6 or 2x-y=-6

x+y=51

using system of equations -

you add the equations -

3x=45

x=15

y=51-x => y=36

hope this helps!!

7 0
3 years ago
VEEL
Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
3 years ago
Please help I need the answer right
Alenkinab [10]

Answer:

B) 4 inches

Step-by-step explanation:

Since ABC is congruent to EFG then AB is congruent to EF, and BC is congruent to FG.

BC = 4 in

FG = 4 in

5 0
3 years ago
A store had 235 MP3 players in the month of January. Every month, 30% of the MP3 players were sold and 50 new MP3 players were s
ozzi
We let f(0) = 235
After 1 month,
f(1) = 235*(0.7) + 50
After 2 months,
f(2) = 235*0.7*0.7+ 50*2
And so on..

Therefore, we can represent the number of MP3 players in the store after n months with the function:
f(n) = 235 (0.7)^n + 50n
8 0
3 years ago
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