First calculate the circumference. Usually this is the diameter times pi, but since we are told to estimate pi, the circumference equals 56 * 22/7 or 176 feet.
In 4 minutes, 4 * 60 = 240 seconds pass. In this time, a 20 second period will occur 240/20 = 12 times.
So we know that the rider rotates 12 times and each rotation takes them 176 feet, meaning that they will travel 12 * 176 = 2112 feet
Answer:
124.12 pounds
Step-by-step explanation:
42.8 x 2.9
= 124.12
= 124.12 pounds
First round
137,638=100,000
52,091=50,000
Then add to get the estamate
100,000
+
50,000
150,000
Then to get the real answer add
1
137,638
+
52091
189,729
1. To answer the questions shown in the figure atttached, it is important to remember that the irrational number e is aldo called "Euler's number" and you can find it in many exercises in mathematics.
2. Then, the irrational number e is:
e=<span>2.71828
</span>
3. When you rounded, you have:
e=<span>2.718
</span>
4. Therefore, as you can see, the the correct answer for the exercise above is the option c, which is: c. 2.718
Answer:
Step-by-step explanation:
A system of linear equations is one which may be written in the form
a11x1 + a12x2 + · · · + a1nxn = b1 (1)
a21x1 + a22x2 + · · · + a2nxn = b2 (2)
.
am1x1 + am2x2 + · · · + amnxn = bm (m)
Here, all of the coefficients aij and all of the right hand sides bi are assumed to be known constants. All of the
xi
’s are assumed to be unknowns, that we are to solve for. Note that every left hand side is a sum of terms of
the form constant × x
Solving Linear Systems of Equations
We now introduce, by way of several examples, the systematic procedure for solving systems of linear
equations.
Here is a system of three equations in three unknowns.
x1+ x2 + x3 = 4 (1)
x1+ 2x2 + 3x3 = 9 (2)
2x1+ 3x2 + x3 = 7 (3)
We can reduce the system down to two equations in two unknowns by using the first equation to solve for x1
in terms of x2 and x3
x1 = 4 − x2 − x3 (1’)
1
and substituting this solution into the remaining two equations
(2) (4 − x2 − x3) + 2x2+3x3 = 9 =⇒ x2+2x3 = 5
(3) 2(4 − x2 − x3) + 3x2+ x3 = 7 =⇒ x2− x3 = −1
