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xz_007 [3.2K]
3 years ago
9

There are 3 consecutive integers that have a sum of 36. What are the integers?

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

<h3>             11, 12, 13</h3>

Step-by-step explanation:

The consecutive integers are increasing by 1

k ← the smallest integer

k+1 ← the middle integer

k+1+1 = k+2   ← the largest integer

k + k+1 + k+2 = 36

   3k + 3 = 36

     ÷3         ÷3

    k + 1  =  12

        -1       -1  

        k  =  11

k+1 = 11 + 1 = 12

k+2 = 11 + 2 = 13

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Divide 190 to the ratio 0.2:0.3:0.5
Lostsunrise [7]
0.2 + 0.3 + 0.5 = 1
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190 x 0.5/1 = 95
   190
0.2: 0.3: 0.5
38: 57: 95
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3 years ago
jan, mya, and Sara ran a total of 64 miles last week. jan and mya ran the same number of miles. Sara ran 8 less miles than mya.
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So,

We'll just use A to represent both Jan and Mya's miles, since they ran the same number.

We have the equations:
1. Jan (J) = Mya (M)
2. Sara (S) = M - 8
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J = M
S = M - 8

We'll just use A to represent both J and M.

S = M - 8

We'll use Elimination by Substitution.
2A + A - 8 = 64

Collect Like Terms
3A - 8 = 64

Add 8 to both sides
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Divide both sides by 3
A = 24

Since
A = J
and
A = M
and
J = M
then
J = 24
M = 24

Substitute
S = 24 - 8
S = 16

Check
24 + 24 + 16 = 64
64 = 64 This checks.

So,
J = 24
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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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