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AlladinOne [14]
3 years ago
15

The slope of a line is -4 and it’s y-intercept is (0,4) what is the equation of the line that is perpendicular to the first line

and passes through (-8,2)
Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Original line equation: y=-4x+4

Perpendicular lines have opposite reciprocals, so the slope of the perpendicular line would be 1/4x.

Perpendicular line equation: y=1/4x+b

Plug in the coordinates that the line passes through to solve for b. Plug -8 in for x and 2 in for y.

2=1/4(-8)+b

Multiply.

2=-2+b

Add 2 to both sides.

4=b

Equation of the perpendicular line: y=1/4x+4

Hope this helps! :)

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Step-by-step explanation:

y(total cost) = x(50 per hour) + 500(y-intercept)

8 0
3 years ago
70 times 10 by the power of 2
Svetradugi [14.3K]

Answer:

I'm not sure which you mean, so I'll give the answer to both:

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8 0
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Without computing, determine which number is greater, [(-4)^4]^5 or -[(4^12)^3 Explain your reasoning.
Strike441 [17]

Answer:

I think [(-4)^4]^5, but I'm not completely sure

Step-by-step explanation:

1.0995116e+12 greater than -4.7223665e+21

[(-4)^4]^5=1.0995116e+12

-[(4^12)^3=-4.7223665e+21

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4 0
2 years ago
Simplify (x^2)^3*5x/6x^2*15x^3
nasty-shy [4]

When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2

<h3>Data obtained from the question</h3>
  • [(x^2)^3 × 5x] / [6x^2 × 15x^3]
  • Simplification =?

<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]

Recall

(M^a)^b = M^ab

Thus,

(x^2)^3 = x^6

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]

Recall

M^a × M^b = M^(a+b)

Thus,

x^6 × 5x = 5x^(6 + 1) = 5x^7

6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5

  • [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5

Recall

M^a ÷ M^b = M^(a - b)

Thus,

5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2

Therefore,

  • [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2

Learn more about algebra:

brainly.com/question/2768008

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8 0
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