Answer:
3
Step-by-step explanation:
all numbers except from zero
that would mean 7 4 and 3
so there would be 3 significant figures
I hope it goes well
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
A = .785 inches ^2
Step-by-step explanation:
C = pi *d
We know the diameter = 2*r
C = pi*2*r
Substituting pi = 3.14 we can solve for r
3.14 = 2*pi*r
3.14 = 2*3.14 *r
Divide by 3.14 on each side
3.14/3.14 = 2*3.14 *r/3.14
1 = 2r
Divide by 2
1/2 =2r/2
1/2 =r
Now we can find the area
A = pi *r^2
A = 3.14 *(1/2)^2
A= 3.14 *1/4
A = .785 inches ^2
Example P: I do my homework
P: I get my allowance
Answer:
HCF×LCM=a×b
6×60=a×b
a×b=360
So the numbers are whose product is 360 and LCM is 60
These two numbers can be 6,60 or 12,30
