Answer:
Step-by-step explanation:
Given that the television show Degenerate Housewives has been successful for many years. That show recently had a share of 18, meaning that among the TV sets in use, 18% were tuned to Degenerate Housewives.
Each household is independent of the other and there two outcomes.
X no of households that are tuned to Degenerate Housewives. is Bin (12, 0.18)
the probability that none of the households are tuned to Degenerate Housewives. P(none) =_______0.0924_____
the probability that at least one household is tuned to Degenerate Housewives. P(at least one) = ____1-0.0924 = 0.9076______
the probability that at most one household is tuned to Degenerate Housewives. P(at most one) = _____0.3359______
If at most one household is tuned to Degenerate Housewives, does it appear that the 18% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Degenerate Housewives unusual?)
No 33% is not unusual.
Mica should have added 2 to 3 instead of 1
Answer:
1. the correct answer is no
2. the correct answer is yes
3. the correct answer is yes
Step-by-step explanation:
-5(4)+2(8) = -4
2(11)-7(3) = 1
1/3(9) - 2(-2) = 7
-6 it is just the opposite of the number. So a positive would be a negative and a negative a positive. So the answer to your question is -6.
