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3 years ago

I need some help; if you don't know the answer, don't answer

Mathematics

2 answers:

ohaa [14]3 years ago

7 0

Answer:

B is the right answer and if you want learn this, than learn algebric expression

masha68 [24]3 years ago

4 0

B is the answer for the question

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What is the slope of the line shown below?

Harman [31]

Answer:

Step-by-step explanation:

Slope is often called rise/run.

This is the amount the line goes upwards, rise, compared to the amount it goes sideways, run.

Compare the two shown points. From the left point the the right, the rise is 6, while the run is 3, creating the rise/run of 6/3. This is simplified to 2.

7 0

2 years ago

Read 2 more answers

When a transversal is perpendicular to two parallel lines, all the angles formed measure 90°. Explain why.

kotykmax [81]

When two parallel lines are cut by a transversal, due to the natures of the different relationships among the angles, all of them will be either equal to the measure of the first angle or equal to that angle subtracted from 180. If the transversal is perpendicular to the parallel lines, forms a right angle, then both the angle given and the angle subtracted from 180 will be 90. This means all of the angles will be 90.

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3 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.

Therefore, the right answer is b. f(x) = 1/2(x + 11)^2 - 5

SECOND.

Translating 8 units to the right:

$g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2$

Then translating 1 unit down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1$

As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.

Therefore, the right answer is a. g(x) = 1/3(x - 8)^2 - 1

7 0

3 years ago

Which of the following is an obtuse triangle ?

vichka [17]

Answer:

A. Triangle B

Step-by-step explanation:

Obtuse angles are greater than 90°, but less than 180°.

I am joyous to assist you anytime.

7 0

3 years ago

Which of the following is true with respect to the following functions:

Mkey [24]

The option that is true with regard to the following functions is Option B. "The domain g(x) and h(x) include all real number while the domain of i(x) and h(x) are restricted"

<h3>What is the explanation for the above?</h3>

Lets examine f(x) = 3x + 14

Note that this function is indicative of a straight-line. See the attached graph for function 1. Note that it doesn't have any end points. That is, it is Asymptote.

Let us examine h(x) = 3ˣ + 1

This represents an exponential graph. Just like the function above it doesn't have any end point. It however has an asymptote:

y = 0

Let us look at F'(x) = Log₃ (x = 1).

This is indicative of logarithm graph. It doesn't have any end but has an asymptote x == 0

Let us take a look at g(x) = X⁴ + 3x² - 14

Notice that in the mid point there is an end point given as (0, -14). Thus, it is correct to state that the function in Option B is the only one that exhibits end behavior and as such is restricted.

Learn more about functions:
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5 0

1 year ago