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konstantin123 [22]
4 years ago
15

The following table shows the length and width of two rectangles:

Mathematics
1 answer:
faltersainse [42]4 years ago
5 0
The perimeter of these can be found by adding length and width and then multiplying by two. 

Rectangle A: (with all of the variables already doubled)
2x + 16 + 2x - 2 
2x + 2x + 16 - 2
4x + 14
So rectangle A's perimeter is 4x + 14.

Rectangle B: (Still with all the variables already doubled)
8x + 10 + 6x - 4
8x + 6x + 10 - 4
14x + 6
So rectangle B's perimeter is 14x + 6

And now to subtract the two.
(7x + 3) - (4x + 14)
14x + 6 - 4x - 14
14x - 4x + 6 - 14
10x - 8

So it would be C.
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Cuál es la probabilidad teórica de obtener un 2 o un 3 al tirar un cubo numérico?
VARVARA [1.3K]

Answer:

c)1/3

Step-by-step explanation:

ya que un dado tiene 6 lados, y usted puede tirar dos números de la muerte de seis caras la respuesta es 1/3\

2/6=1/3

4 0
4 years ago
A triangle contains angles of 95° and 35°. what is the measure of the third angle of the triangle ?​
PilotLPTM [1.2K]

Answer:

50

Step-by-step explanation:

Add up the two known angle measurements:

95+35=130

Subtract this number from 180°:

180-130=50

Write down your answer

95+35+25=180

*The three angles should add up to 180° for the triangle to exist*

I hope that helped

6 0
3 years ago
Read 2 more answers
A 12 foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the
ira [324]

Using Pythagoras theorem, the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.                      

Let distance from the wall to the foot of the ladder is 'x' feet and the height of the top of the ladder is 'y' feet.

Pythagoras theorem, x^{2} + y^{2} = (12)^{2}       --->(1)

Given,\frac{dx}{dt}= 2feet/second   at x=3

Put x=3 in Pythagoras theorem equation (1)

(3)^{2} + y^{2} = 144

         y^{2} = 144 - 9

        y^{2}  =  135

        y = 11.61

Derive equation (1) w.r.t to 't'

2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0                ---->(2)

substitute the value of 'x', 'dx/dt' and 'y' in equation (2), we get the fast of the top of the ladder moving down when the foot of the ladder is 3 feet from the wall

2(3)(2) + 2 (11.61)\frac{dy}{dt}  = 0

12 + 23.22 \frac{dy}{dt}  = 0

                  \frac{dy}{dt}= \frac{-12}{23.22}

                  \frac{dy}{dt} = -0.518

Hence,  using Pythagoras theorem the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.  

Learn more about Pythagoras theorem here

brainly.com/question/21511305  

#SPJ4    

     

5 0
2 years ago
For the equation y=5x+4, determine the value of y when x=-3​
Norma-Jean [14]

Answer:

y=-11

Step-by-step explanation:

y=5x+4\\y=5\left(-3\right)+4\\y=-5\cdot \:3+4\\y=-15+4\\y=-11

6 0
2 years ago
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The correct answer should be Choice B. 

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