Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Answer:
1/216
1/8 *1/3³ ( cross multiply ) = 1/216
Did you only need the answer for the one on the top right?? Or all of them because If you need all of them I can do that too I am just assuming you just needed that one because it was selected.
Answer: <em>$119</em>
Step-by-step explanation:
<em>Let's take this equation</em>
<em>85(n)</em>
<em>n will equal 1.40 as the price mark up is 140%</em>
<em>85(1.40)</em>
<em>$119</em>