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Mnenie [13.5K]
3 years ago
6

The area of the figure below issquare units?​

Mathematics
1 answer:
enyata [817]3 years ago
6 0

The area of the figure is 27.5 square units.

Solution:

The given image is a trapezium.

Count the small boxes to find the length.

Length of top base (b_1) = 4 units

Length of bottom base (b_2) = 7 units

Height of the trapezium = 5 units

Area of the trapezium:

$A=\frac{1}{2}\times (b_1+b_2)\times h

$A=\frac{1}{2}\times (4+7)\times 5

$A=\frac{1}{2}\times 11\times 5

$A=\frac{1}{2}\times 55

A = 27.5 square units.

The area of the figure is 27.5 square units.

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Answer:

​x=

​16

​

​333

​​  

​y=

​8

​

​283

​​  

Step-by-step explanation:

1 Solve for yy in 13+2x+y+90=18013+2x+y+90=180.

y=-2x+77y=−2x+77

2 Substitute y=-2x+77y=−2x+77 into 4x+1+8x-2y=1804x+1+8x−2y=180.

16x-153=18016x−153=180

3 Solve for xx in 16x-153=18016x−153=180.

x=\frac{333}{16}x=

​16

​

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​​  

4 Substitute x=\frac{333}{16}x=

​16

​

​333

​​  into y=-2x+77y=−2x+77.

y=\frac{283}{8}y=

​8

​

​283

​​  

5 Therefore,

\begin{aligned}&x=\frac{333}{16}\\&y=\frac{283}{8}\end{aligned}

​

​

​​  

​x=

​16

​

​333

​​  

​y=

​8

​

​283

​​  

​​  

Done

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