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3 years ago

Average of 2.24 4.63

Mathematics

2 answers:

solong [7]3 years ago

6 0

Answer:

3.45

Step-by-step explanation:

add them together and divide by two

kotykmax [81]3 years ago

6 0

Answer:

3.43500

Step-by-step explanation:

You will add your given decimals

The answer you get out you will divide by 2

This might or might not be the right answer but this is my solution for this question

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The coordinates of a point and its images are given. Is the reflection in the

Lemur [1.5K]

Answer:

The reflection is in the y-axis cause the y point went from -7 to 7 and the x point stayed the same.

4 0

2 years ago

If line segment AB measures approximately 8.6 units and is considered the base of parallelogram ABCD, what is the approximate co

liraira [26]

Answer:

about 4.8 units

Step-by-step explanation:

6 0

2 years ago

Solve the equation: k^2+5k+13=0

mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\$

From the question

a = 1 , b = 5 , c = 13

So we have

$k = \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)} \\ = \frac{ - 5 \pm \sqrt{25 - 52} }{2} \\ = \frac{ - 5 \pm \sqrt{ - 27} }{2} \: \: \: \: \: \: \\ = \frac{ - 5 \pm3 \sqrt{3} \: i}{2} \: \: \: \: \: \:$

<u>Separate the solutions</u>

$k_1 = \frac{ - 5 + 3 \sqrt{3} \: i }{2} \: \: \: \: or \\ k_2 = \frac{ - 5 - 3 \sqrt{3} \: i}{2}$

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

$k_1 = - \frac{5}{2} + \frac{3 \sqrt{3} }{2} \: i \: \: \: \: or \\ k_2 = - \frac{5}{2} - \frac{3 \sqrt{3} }{2} \: i$

Hope this helps you

8 0

2 years ago

Which fraction is equivalent to 1/3?

Svetllana [295]

Answer:2\6 or 4\12 etc.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.

Tpy6a [65]

For this case we have that by definition, the equation of a line in the point-slope form is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

m: It is the slope of the line and $(x_ {0}, y_ {0})$ is a point through which the line passes.

We have the following equation of the slope-intersection form:

$y = 4x + 1$

Where the slope is $m = 4$

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

$m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}$

Thus, the equation will be of the form:

$y-y_ {0} = - \frac {1} {4} (x-x_ {0})$

Finally we substitute the given point and we have:

$y-3 = - \frac {1} {4} (x-6)$

Answer:

Option B

8 0

3 years ago