3 years ago

Hey I need help on this like really fast

Mathematics

1 answer:

asambeis [7]3 years ago

3 0

Answer: what are you trying to answer

Step-by-step explanation:

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2 years ago

During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the

mars1129 [50]

Answer:

Yes, it will reach or exceed 141 degree F

Step-by-step explanation:

Given equation that shows the temperature T in degrees Fahrenheit x minutes after the machine is put into operation is,

$T = 0.005x^2 + 0.45x + 125$

Suppose T = 141°F,

$\implies 141 = 0.005x^2 + 0.45x + 125$

$\implies 0.005x^2 + 0.45x + 125 - 141 =0$

$\implies 0.005x^2 + 0.45x - 16=0$

Since, a quadratic equation $ax^2 + bx + c =0$ has,

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If Discriminant, $D = b^2 - 4ac \geq 0$

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If D < 0,

Since, $0.45^2 - 4\times 0.005\times -16 = 0.2025 + 32 > 0$

Thus, roots of -0.005x² + 0.45x + 125 are real.

Hence, the temperature can reach or exceed 141 degree F.

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3 years ago

F(x) = x+3

Ksivusya [100]

Answer:

I got 2x^3+3x^2-4x-12

Step-by-step explanation:

I hope this helps a little bit

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1 year ago

Factor the sum of terms as a product of the gcf and a sum<br><br> 18+20

iVinArrow [24]

The gcf of 18 and 20 is 2, so your answer is:

2(9+10)

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3 years ago

Which of the following best describes the pattern in the diagram as you move

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Answer:

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Step-by-step explanation:

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2 years ago

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