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ankoles [38]
3 years ago
13

if a department store has a 20% off sale with and additional 7% off, what percent off should they display?

Mathematics
1 answer:
Sonja [21]3 years ago
6 0

Answer:

they should display 27% off sale

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Each day of overtime you work, you earn an additional $50 more than your regular pay of $100 a day.
GaryK [48]

The answer should be $650 because, $100 a day for five days is $500. Then the overtimes for three days would equal up to $150 in overtime. $500 + $150 = $650

7 0
3 years ago
The earth travels 1,050 miles per hour.
lesantik [10]

The earth travels 1,050 miles in an hour.

There are 24 hours in a day.

So multiply 1,050 by 24.

And you get 25,200.

The earth travels 25,200 miles in a day.

5 0
3 years ago
45% of what number is 27?
gtnhenbr [62]
45% of what number is 27

0.45x = 27
x = 27 / 0.45
x = 60 <== 45% of 60 = 27
5 0
4 years ago
Scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 17. Use the empirical rule
-BARSIC- [3]

Answer:

(a) 95% of people have an IQ score between 66 and 134.

(b) 32% of people have an IQ score of less than 83 or greater than 117​.

(c) 16% of people have an IQ score greater than 117.

Step-by-step explanation:

We are given that scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 17.

Let X = <u><em>scores of an IQ test</em></u>

SO, X ~ Normal(\mu=100, \sigma^{2} = 17^{2})

The z-score probability distribution for the normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

<u>Now, the empirical rule states that;</u>

  • 68% of the data values lie within 1 standard deviation from the mean.
  • 95% of the data values lie within 2 standard deviations from the mean.
  • 99.7% of the data values lie within 3 standard deviations from the mean.

(a) The percentage of people having an IQ score between 66 and 134 is given by;

     z score for 66 =  \frac{X-\mu}{\sigma}  =  \frac{66-100}{17}  = -2

     z score for 134 =  \frac{X-\mu}{\sigma}  =  \frac{134-100}{17}  = 2

This means that the percentage of people having an IQ score between 66 and 134 is 95%.

(b) Firstly, we have to find the percentage of people having an IQ score between 83 and 117;

     z score for 83 =  \frac{X-\mu}{\sigma}  =  \frac{83-100}{17}  = -1

     z score for 117 =  \frac{X-\mu}{\sigma}  =  \frac{117-100}{17}  = 1

This means that the percentage of people having an IQ score between 83 and 117 is 68%.

This means that the percentage of people having an IQ score of less than 83 or greater than 117 = 100% - 68% = 32%.

(c) In the above part, we find that there are 32% of the values that have an IQ score of less than 83 or greater than 117.

This means that half of this will be less than 83 and half of this will be greater than 117.

So, the percentage of people having an IQ score greater than 117​ = \frac{32\%}{2} = 16%.

8 0
3 years ago
What is the probability of getting 60% or better on a true false exam with 50 questions
Ipatiy [6.2K]

Answer:

41.1764...%

Step-by-step explanation:

60% on 50 questions is 30/50 correct since 30÷50=.6=60%

Between 30 and 50(inclusive) there are 21 numbers.(30,31,32...49,50).

There are 51 possibilities of scores,1-50/50 or 0/50

21/51=0.411764...

3 0
4 years ago
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