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3 years ago

Factor 15x3-5x2+6x-2by grouping.what is the resulting expression?

Mathematics

1 answer:

Valentin [98]3 years ago

6 0

15x3 - 5x2 + 6x - 2
= 5x2(3x - 1) + 2(3x - 1)
= (5x^2 + 2)(3x - 1) answer

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Can somebody answer this worksheet. Sorry before it didnt let me.

Ahat [919]

Answer:

1: L = 5

W = 7

2: A = lw

3: 35

4: 18

5: You have to add them up because it is 1 shape broken up into different parts.

6: 53

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2 years ago

The results of a linear regression are shown below.

IgorLugansk [536]

Hello!

As we can see, our a value, which would be the coefficient of $x$ , which determines our slope, is negative, meaning that this whole line is negative.

Furthermore, the correlation can be determined using the r value of the linear regression, which is around -0.9.

If the r value of the linear regression is close to 1 or -1, let's say around |r| > 0.8, then we can consider the regression a strong correlation, meaning that this is a strong negative correlation, which is answer choice A.

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2 years ago

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

3 years ago

If f(x) = x2 − x − 12 and g(x) = x2 − 16, find f(x) × g(x).

Andreyy89

Answer:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

Step-by-step explanation:

We have the function f(x) = x^2 − x − 12 and g(x) = x^2 − 16 and we need to find the multiplication of both functions.

f(x) × g(x) = ( x^2 − x − 12)(x^2 − 16) = x^4 - 16x^2 -x^3 + 16x -12x^2 + 192

Simplifying:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

7 0

2 years ago

Read 2 more answers

The graph shows the distance, y, in miles, of an eagle from its nest over a certain amount of time, x, in minutes.

miv72 [106K]

i think its A but I'm not 100% on it-

4 0

2 years ago