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3 years ago

25POINTS!!!

2 answers:

4 0

i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point.

So t is perpendicular to JL

let l be the tangent line through L. Then l is perpendicular to JL

ii. So t and l are 2 different lines, both perpendicular to line JL.

2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.

Remark. Draw a picture to check the steps

natta225 [31]3 years ago

4 0

JL is a diameter of circle K. If tangents to circle K are constructed through points L and J, then the two tangents will be parallel because the tangent at a point on a circle is perpendicular to the diameter.

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Since the linear equation for x. -4.8(6.3x-4.18) = -58.56

Oliga [24]

I believe x is equal to 13/5

8 0

4 years ago

Read 2 more answers

last week the cost of a tank of gas increased by $1.64 express this increase as a mixed number in simplest form

svetoff [14.1K]

1 16/25. This is because 1 64/100 reduces to 32/50 which reduces further to create 16/25

5 0

3 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint 1: (-10,6) midpoint: (7,-6)

blsea [12.9K]

The other end point is (24, -18)

Solution:

Given that,

Endpoint 1 is (-10, 6)

Midpoint is: (7, -6)

We have to find the other endpoint

The midpoint is given by formula:

$M(x, y) = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})$

From given,

$M(x, y) = (7, -6)\\\\(x_1, y_1) = (-10, 6)\\\\(x_2, y_2) = ?$

Substituting the values we get,

$(7, -6) = (\frac{-10+x_2}{2} , \frac{6+y_2}{2})$

On comparing both sides we get,

$7 = \frac{-10+x_2}{2} \text{ and } -6 = \frac{6+y_2}{2}\\\\14 = -10 + x_2 \text{ and } -12 = 6 + y_2\\\\x_2 = 24 \text{ and } y_2 = -18$

Thus the other end point is (24, -18)

3 0

4 years ago

A man wants to make up 100 one-pound jars of nuts to sell for 66 cents a jar. He plans to use 40 pounds of nuts worth 75 cents a

kari74 [83]

Answer:

60 cents per pound.

Step-by-step explanation:

Let x represent the cost of other type of nuts in cents.

We have been given that a man wants to make up 100 one-pound jars of nuts and he plans to use 40 pounds of nuts worth 75 cents a pound.

The pounds of other types of nuts would be 100 pounds minus 40 pounds that is equal to 60 pounds.

The total cost of 60 pounds of other type of nuts would be $60x$ .

The total cost of 40 pounds of nuts worth 75 cents per pound would be $40\times 75=3000$ .

The cost of 60 pounds of other nuts and 40 pounds of nuts worth 75 cents per pound would be equal to total cost of 100 pounds of nuts worth 66 cents per pound.

We can represent this information in an equation as:

$60x+3000=100(66)$

$60x+3000=6600$

$60x+3000-3000=6600-3000$

$60x=3600$

$\frac{60x}{60}=\frac{3600}{60}$

$x=60$

Therefore, the other type of nuts are worth 60 cents per pound.

6 0

4 years ago

Pls answer will choose brainliest

MrRissso [65]

Hi ;-)

$\text{x}=-1 \ \text{and} \ \text{y}=-4\\\\\dfrac{5x^2-y^2+3}{2x-4y}=\dfrac{5\cdot(-1)^2-(-4)^2+3}{2\cdot(-1)-4\cdot(-4)}=\dfrac{5\cdot1-16+3}{-2+16}=\boxed{-\frac{8}{14}}$

4 0

3 years ago