Answer:
i would say wind because like the tidal power plants, the wind turns the turbines generating energy
Explanation:
Site-specific recombination systems all of the choices are correct i.e.
A. do not depend on extensive nucleotide sequence homology.
B. depend on enzymes that are often specific for sequences within the host.
C. are features of some viruses.
- An exchange between two specified sequences (target sites), either on the same DNA molecule or on two separate DNA molecules, is known as site-specific recombination.
- DNA sequences may be integrated, excised, or inverted as a result of the exchange.
- A site-specific recombinase that can work by itself or with the aid of additional components or enzymes shapes the DNA target during recombination.
- The recombinase is chemically bonded to the ends of the intermediate DNA after DNA breakage at the recombination site; when this process is reversed, the intermediate DNA is resealed to form the recombinant and the recombinase is released.
- During this recombination process, neither replication nor repair are necessary.
learn more about Site-specific recombination here: brainly.com/question/11458760
#SPJ4
Answer:
The coronavirus speads mainly from person to person. This can happen between people who are in close contact with one another. Droplets that are produced when a infected person coughs or sneezes may land in the mouths or noses of people who are nearby, or possibly be inhaled into their lungs
Answer:
0.153
Explanation:
We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.
So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.
ρVg = ρ'V'g + ρ"V"g
ρV = ρ'V'g + ρ"V"
Its new body volume = volume of water displaced, V = V' + V"
ρ(V' + V") = ρ'V' + ρ"V"
ρV' + ρV" = ρ'V' + ρ"V"
ρV' - ρ"V' = ρ'V" - ρV"
(ρ - ρ")V' = (ρ' - ρ)V"
V'/V" = (ρ - ρ")/(ρ' - ρ)
= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)
= (0.9988 g/cm³ ÷ 0.18 g/cm³)
V'/V" = 5.55
Since V = V' + V"
V' = V - V"
(V - V")/V" = 5.55
V/V" - V"/V" = 5.55
V/V" - 1 = 5.55
V/V" = 5.55 + 1
V/V" = 6.55
V"/V = 1/6.55
V"/V = 0.153
So, the fish must inflate its air sacs to 0.153 of its expanded body volume
