A new surgical procedure is said to be successful 60% of the time. Suppose the operation is performed five times and the results
1 answer:
Answer:
0.07776, 0.3456,0.08704
Step-by-step explanation:
Given that a new surgical procedure is said to be successful 60% of the time
Let X be the no of successes
Then X has only two outcomes and each trial is independent of the other
Hence X is binomial with p = prob of success in a single trial = 0.60
n = Number of operations performed = 5
Prob that
a) all five operations are successful =
(b) exactly three are successful
=
(c) less than two are successful
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2 + 2tan^2 x + tan^2 x - 3 = 0
3tan^2 x = 1
tan^2 x = 1/3
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2(1 + tan^2 x) + tan^2 x - 3 = 0 [sec^2 x = 1 + tan^2 x]
2 + 2tan^2 x + tan^2 x - 3 = 0
3tan^2 x = 1
tan^2 x = 1/3