<span>Here is what I got for the first one.
MAD= 1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|) =1/5(|85-83|+|83-83|+|87-83|+|90-83|+|70-83|) =1/5(2+0+4+7+13)) =5.2
And for the second one I got,
MAD= 1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|) =1/5(|75-76|+|74-76|+|68-76|+|83-76|+|80-76|) =1/5(1+2+8+7+4)) =4.4
answer = 4.4
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Answer:
the answer is 13.5
Step-by-step explanation:
A=105
B=4
C=7
so you just plug in using the trigonometric formula for area which in this case would be
1/2(4)(7)sin(105)
then you just type that into a graphing calculator (make sure its set to degrees) then you get 13.52 which would be 13.5 rounded.
Answer:
yes
Step-by-step explanation:
Answer:
7/2 = m
Step-by-step explanation:
We can use cross products to solve
3 6
--- = ------
m 7
3*7 = 6*m
Divide each side by 6
21/6 = 6m/6
7/2 = m
Answer:
7x21
Step-by-step explanation:
First, we need to find the length of the pool. Since it is three times as long as it is wide, it is 21 feet long (7 x 3 = 21). That way we can tell that it is 7x21, with a perimeter of 56 feet, and an area of 147 feet squared.
