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Snezhnost [94]
3 years ago
6

1. Name the vertex of angle 2.

Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:

1) YTW

2) WT, TZ

3) UTZ

4) Right angle

  Acute angle

  Obtuse angle

  Right angle

5) TU

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My professor showed us in class today how to use ode45 to solve a differential equation numerically. i would like to use it on m
Brilliant_brown [7]

Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.

For example, if you have

... u'' + a·u' + b·u = f

you can define u1 = u, u2 = u' and now you have the system

... (u2)' + a·u2 + b·u1 = f

... (u1)' = u2

Rearranging, this is

... (u1)' = u2

... (u2)' = f - a·u2 - b·u1

ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.

7 0
3 years ago
Obtain the required confidence interval for the difference between two population proportions. Assume that independent simple ra
Thepotemich [5.8K]

Answer:

The 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program = ( -0.293, 0.023)

Step-by-step explanation:

The formula for confidence interval for the difference between the proportions is given as:

p1 - p2 ± z × √p1 (1 - p1)/n1 + p2(1 - p2)/n2

From the question

We have two groups.

Group 1 = For women

A survey found that 37 of 74 randomly selected women

p1 = x/n1

n1 = 74

x1 = 37

p1 = 37/74

p1 = 0.5

Group 2 = For Men

A survey found out that 47 of 74 randomly selected men follow a regular exercise program

p2 = x/n1

n2= 74

x2 = 47

p2 = 47/74

p2 = 0.6351351351 ≈ 0.635

z = z score for 95% Confidence Interval = 1.96

The confidence interval for the difference between the proportions is given as:

p1 - p2 ± z × √p1 (1 - p1)/n1 + p2(1 - p2)/n2

0.5 - 0.635 ± 1.96 × √0.5 (1 - 0.5)/74 + 0.635(1 - 0.635)/74

-0.135 ± 1.96 × √(0.5 × 0.5)/74 + (0.635× 0.365)/74

-0.135 ± 1.96 × 0.08068750209663572

-0.135 ± 0.158147504109406

Hence:

= -0.135 - 0.158147504109406

= -0.2931475041

Approximately = -0.293

= -0.135 + 0.158147504109406

= 0.0231475041

Approximately = 0.023

Therefore, the 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program = ( -0.293, 0.023)

6 0
3 years ago
(-2) + (3 - 7)<br> (-1) * (-2)
valentinak56 [21]

Answer:

  1. -6
  2. 2

Step-by-step explanation:

( - 2) + ( 3 - 7)

- 2 + (3 - 7)

- 2 +  - 4

- 2 - 4

\boxed{\green{ =  - 6}}

◇◇•◇◇

( - 1) \times ( - 2)

1 \times 2

\boxed{\green{= 2}}

4 0
3 years ago
​A manager wants to know if the mean productivity of two workers is the same. For a random selection of 30 hours in the past​ mo
vekshin1

Answer:

A.The data should be treated as paired samples. Each pair consists of an hour in which the productivity of the two workers is compared.

Explanation:

If the mean productivity of two workers is the same.

For a random selection of 30 hours in the past month, the manager compares the number of items produced by each worker in that hour.

There are two samples and the productivity of the two men is paired for each hour.

7 0
3 years ago
2.a)Find the prime factorizations of 90 and 168.
balu736 [363]
90|2\\45|3\\15|3\\.\ 5|5\\.\ 1|\\\\90=2\cdot3\cdot3\cdot5\\\\168|2\\.\ 84|2\\.\ 42|2\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\168=2\cdot2\cdot2\cdot3\cdot7

100|2\\.\ 50|2\\.\ 25|5\\.\ \ 5|5\\.\ \ 1|\\\\100=2\cdot2\cdot5\cdot5\\\\126|2\\.\ 63|3\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\126=2\cdot3\cdot3\cdot7
4 0
3 years ago
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