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Kisachek [45]
3 years ago
5

If Bart has 20$ and Andy took $19.65 how much does Bart have

Mathematics
1 answer:
Helen [10]3 years ago
8 0

Answer:

well bart has 20.00

andy took      19.65

Step-by-step explanation:

subtract 20.00\\-19.65\\\\_______\\0.35

your answer should be 0.35

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Solve 8x = 1 quick plz
Ulleksa [173]

Answer:

x = 1/8 = 0.125

Step-by-step explanation: Add 1 to both sides of the equation :

8x = 1

Divide both sides of the equation by 8:

x = 1/8 = 0.125

4 0
4 years ago
80km is 9% of what distance?
seropon [69]

Answer:

  888.89 km

Step-by-step explanation:

Write the given question as an equation and solve.

  80 km = 0.09 × (what distance)

  (80 km)/0.09 = what distance . . . . . divide by the coefficient of the variable

  888.89 km ≈ what distance

80 km is 9% of 888.89 km

3 0
3 years ago
If a = 31, what is the circumference of the circle? (Round to one decimal place.)
gregori [183]

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3 0
3 years ago
Read 2 more answers
Eric’s average income for the first 4 months of the year is $1,450.25, what must be his average income for the remaining 8 month
UNO [17]

Answer:

$1946

Step-by-step explanation:

His average for the first four months

= $1,450.25

So he earned 4*$1,450.25

= $5801 for the first four months.

Then for the year his average is $1,780.75.

So he earned $1,780.75*12 for the year.

=$ 21369

So the amount he earned for the remaining 8 months was 21369-5801

= $15568

The average for the 8 Months= 15568/8

= $1946

5 0
3 years ago
A 25​-foot ladder is placed against a vertical wall. Suppose the bottom of the ladder slides away from the wall at a constant ra
dsp73

Answer: The ladder is sliding down the wall at a rate of 5\dfrac{17}{50}\ ft/sec

Step-by-step explanation:

Since we have given that

Length of ladder = 25 foot

Distance from the wall to the bottom of ladder = 15 feet

Let base be 'x'.

Let length of wall be 'y'.

So, by pythagorus theorem, we get that

x^2+y^2=25^2\\\\15^2+y^2+625\\\\225+y^2=625\\\\y^2=625-225\\\\y^2=400\\\\y=\sqrt{400}\\\\y=20\ feet

\dfrac{dy}{dx}=-4\ ft/sec

Now, the equation would be

x^2+y^2=625\\

Differentiating w.r.t x, we get that

2x\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0\\\\2\times 15\dfrac{dx}{dt}+2\times 20\times -4=0\\\\30\dfrac{dx}{dt}-160=0\\\\\dfrac{dx}{dt}=\dfrac{160}{30}=5.34\ ft/sec

Hence, the ladder is sliding down the wall at a rate of 5\dfrac{17}{50}\ ft/sec

8 0
4 years ago
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