The set of integers is closed under addition, subtraction, and multiplication because when i add, subtract, or multiply any integers, the result is always an integer.
The table of values of the function y = ∛x is
x y
-8 -2
-1 -1
0 0
1 1
8 2
<h3>How to fill in the y values?</h3>
The function is given as:
y = ∛x
When x = -8, we have:
y = ∛-8 = -2
When x = -1, we have:
y = ∛-1 = -1
When x = 0, we have:
y = ∛0 = 0
When x = 1, we have:
y = ∛1 = 1
When x = 8, we have:
y = ∛8 = 8
So, the table of values is
x y
-8 -2
-1 -1
0 0
1 1
8 2
Read more about cubic functions at:
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(10x 5 - 3x 6)
(50x - 18x)
(f-g) = 32x
If x + y = 6, then solve for y to get: y = 6 - x.
Now replace y with 6 - x in both equations.
(5x)/3 + 6 - x = c
2(6 - x) = c - 4x
The upper equation is solved for c.
Now we solve the lower equation for c.
c = 2(6 - x) + 4x
c = 12 - 2x + 4x
c = 2x + 12
Since we have two equations solved for c, we substitute to get
(5x)/3 + 6 - x = 2x + 12
This is an equation in only x, so we can solve for x.
(5x)/3 - 3x = 6
5x - 9x = 18
-4x = 18
x = -9/2
Now we solve for y.
x + y = 6
-9/2 + y = 6
y = 9/2 + 12/2
y = 21/2
Now we solve for c.
c = (5x)/3 + y
c = (5 * (-9/2))/3 + 21/2
c = -45/6 + 21/2
c = -15/2 + 21/2
c = 6/2
c = 3
Answer: c = 3
