What is the perimeter, P, of a rectangle that has a length of x + 8 and a width of y − 1?
2 answers:
Answer:
P = 2x + 2y + 14
Step-by-step explanation:
Answer:
P = 2x + 2y + 14
Step-by-step explanation:
Length (L) = x + 8 units
Width (W) = y - 1 units
Perimeter (P) = 2L + 2W
P = 2(x + 8) + 2(y - 1)
P = 2x + 16 + 2y - 2
P = 2x + 2y + 16 - 2
P = 2x +2y + 14
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