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Ymorist [56]
4 years ago
8

#1 The area of a rectangular deck, in square meters, is given by the polynomial 40p^2 + 24p.

Mathematics
1 answer:
Murrr4er [49]4 years ago
3 0

Answer:

1.

a. 5p + 3

b. 26p + 6

2.

a r = (v ÷(pi)h)½

b. r = 3.74 to the nearest hundredth

Step-by-step explanation:

1.

Area of deck = 40p² + 24p

Width of deck = 8p

Area = length × width(breadth)

a. Area = length × width

40p² + 24p = length × 8p

Factorise out 8p from the left hand side

8p(5p + 3) = length × 8p

Divide both sides by 8p

5p + 3 = length

b Perimeter of deck = 2 (length + width)

"" = 2(5p+3 + 8p)

"" = 2 (13p + 3)

"" = 26p + 6

2.

Volume = 200 mm³

Height = 17mm

a. isolate the r in the equation v = (pi)r²h

v = (pi)r²h

Divide both sides by (pi)h

v ÷ (pi)h = r²

Take the square roots of both sides

(v ÷ (pi)h)½ = r

b. find r using your answer in a.

r = (v ÷ (pi)h)½

r = (200 ÷ ( 22/7 × 17))½

r = (200 ÷ 53.4286)

r = 3.7433

r = 3.74 to the nearest hundredth

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<u>the question is </u> Calculate the value of the copper in the coin

Step 1

Find the volume of the coin

we know that

the volume of a cylinder is equal to

V=\pi r^{2}h

where

r is the radius of the coin

h is the thickness of the coin

in this problem we have

Diameter=19 mm=1.9 cm

r=D/2------> r=1.9/2=0.95 cm

h=1.5 mm=0.15 cm

substitute the values in the formula

V=\pi*0.95^{2}*0.15=0.425\ cm^{3}

Step 2

<u>Find the mass of copper in the coin</u>

we know that

the density is equal to

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Solve for the mass

mass=Density*volume

we have

Density=8.9\ gr/cm^{3}\\Volume=0.425\ cm^{3}

substitute in the formula

mass=8.9*0.425=3.785\ gr

Step 3

<u>Find the cost</u>

we know that

the market price of the copper is $2.15 per pound

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0.0083*$2.15=$0.018=$0.02

therefore

<u>the answer is</u>

$0.02

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4 years ago
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