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jasenka [17]
3 years ago
12

(x2−1)(x+1)≥0. pls help me​

Mathematics
1 answer:
docker41 [41]3 years ago
7 0

Step-by-step explanation:

(x²-1)(x+1)≥0

As it has two multiples,

Therefore,

Either,

x²-1≥0

x²≥0+1

x²≥1

x≤√1

x≤1

Or,

x+1≥0

x≥-1

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The length of a 10-minute video is decreased by 45% when the video is edited. What is the length of the edited video?
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Answer:

The edited video would now be 5 Minutes 50 Seconds

Step-by-step explanation:

10-4.5=5.5

To subtract any percentage from a number, simply multiply that number by the percentage you want to remain. In other words, multiply by 100 percent minus the percentage you want to subtract, in decimal form. To subtract 20 percent, multiply by 80 percent (0.8).

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3 years ago
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The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.
koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

  • Revenue is <u>Q₂ < $7,500 < Q₃</u>
  • The sales for the week is better than <u>72.91%</u> of all sales

The performance for the week for Bridge Road

  • Revenue; <u>Q₂ < $7,100 < Q₃</u>
  • The sale for the week is better than <u>59.87%</u> of all sales

(b) The mean is <u>$3611</u>

The median is $<u>3,600</u>

The standard deviation is $<u>3250</u>

The Interquartile range is $<u>6075</u>

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

Z = \dfrac{x - \mu }{\sigma }

  • Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193

From the Z-Table, we have;

The percentile= 0.7291

  • Therefore, the sale for the week for Park Street is better than <u>72.91%</u> of all the sales

Park Street revenue;

The z-score is given as follows;

  • Z = \dfrac{7500 - 6611}{3580} \approx 0.25

From the Z-Table, we have;

The percentile = <u>0.5987</u>

  • Therefore, the sale for the week is better than <u>59.87 %</u> of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

  • The new mean = <u>$3,611</u>

The new median = 6600 - 3000 = 3600

  • The new median = <u>$3,600</u>

The standard deviation and the interquartile range remain the same, therefore, we have;

  • The standard deviation = <u>$3,580</u>

The interquartile range = 9675 - 3600 = 6075

  • The interquartile range = <u>6075</u>

Learn more here:

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