What are the roots of the polynomial equation? x2−12x−64=0

2 answers:

8 0

Answer: " x = 16 ; - 4 " .
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<u>Note</u>:
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-16 , +4 = -12 .

-16 * 4 = -64
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(x - 16)(x + 4) = 0 ;
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x = 16 ; - 4 .
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Mariana [72]3 years ago

8 0

X² -12x -64=0
D=b² - 4ac=144+4*64=400

x=(-b+/-√D)/2a

x=(12+/-20)/2
x1=32/2=16
x2=-8/2= -4

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Given f(x) and g(x) = f(x + k), use the graph to determine the value of k.

dedylja [7]

g(x) is basically transformed f(x). First, let's focus on f(x) graph. Notice how the graph has slope of 1 and intersect y-axis at (0,0).

Which means that our equation for f(x) is:

$\large{f(x) = x}$

Now then we focus on g(x). g(x) is f(x+k). That means if f(x) = x then f(x+k) would mean substitute x = x+k in the equation.

$\large{f(x + k) = x + k }\\ \large{g(x) = x + k}$

Next, we want to find the value of k. In the slope-intercept form or y = mx+b where m = slope and b = y-intercept. Notice the g(x) graph and see that the graph intersects y-axis at (0,4). Therefore k = y-intercept = 4.

$\large{g(x) = x + 4}$