What are the roots of the polynomial equation? x2−12x−64=0
2 answers:
Answer: " x = 16 ; - 4 " .
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<u>Note</u>:
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-16 , +4 = -12 .
-16 * 4 = -64
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(x - 16)(x + 4) = 0 ;
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x = 16 ; - 4 .
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X² -12x -64=0
D=b² - 4ac=144+4*64=400
x=(-b+/-√D)/2a
x=(12+/-20)/2
x1=32/2=16
x2=-8/2= -4
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