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12345 [234]
3 years ago
7

Best estimate for 1kg =1,000g

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0
I think the answer is 1g

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The sum of a number m and 7.1
bekas [8.4K]
7.1+m

Or if you needed to add a variable to be the answer it would be 7.1+m=x
4 0
3 years ago
Consider a multiple choice exam with 10 questions, and with 4 possible answers to each question (labeled A, B, C, and D). 1a. Wh
mrs_skeptik [129]

Answer:

(1a) 9.54e-07 (1b) 0.9437 (2) 10^8

Step-by-step explanation:

We have n = 10 questions. For each question in the multiple choice exam, we can choose the correct answer with probability p = 0.25 or an incorrect answer with probability q = 0.75 (just by guessing). Besides is reasonable to believe that questions are independent. Let X be the random variable that represents the number of correct answers (just by guessing) observed during the n = 10 questions, so, X have a binomial distribution.

(a) The probability of getting a perfect score just by guessing is

P(X = 10) = 10C10(0.25)^{10}(0.75)^{10-10} = 9.54e-07

(b) The probability of getting at least one question correct, just by guessing

P(X\geq1) = \sum_{x=1}^{x=10}10Cx(0.25)^{x}(0.75)^{(10-x)} = 0.9437

2. Each RUID is 9-digits long, there are 10 digits, each of the nine positions for a digit of the RUID has 10 posibilities except the 4th and 5th positions which must be both 0. For the multiplication rule there can be (10)^3(1)(1)(10)^5 = 10^8 different RUIDS.

3 0
3 years ago
A teacher orders 20 copies of a new graphic novel for his class to read. Each of the books weighs the same amount. The total wei
Maksim231197 [3]

Answer:

Each book weighs 1/2 lbs

Step-by-step explanation:

Take the total weight and divide by the number of books

10 lbs/20 books

1/2 lbs per book

Each book weighs 1/2 lbs

5 0
3 years ago
Solve please -3x-27=
juin [17]

Answer:

−3(x+9)

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Commuting. there are two routes he could take to work. Aneighbor who has lived there a long time tells him Route Awill average 5
iren2701 [21]

Answer:

a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.  

(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.

Step-by-step explanation:

Given:  

n_1 = 20

x_1= 40

s_1 = 3

n_2 = 20

x_2= 43

s_2 = 2

d_f = 33.1

c = 95%. 0.95

(a) Determine the t-value by looking in the row starting with degrees of freedom df = 33.1 > 32 and in the column with c = 95% in the Student's t distribution table in the appendix:  

t\alpha/2 = 2.037  

The margin of error is then:  

E = t\alpha/2 *√s_1^2/n_1+s_2^2/n_2

E = 2.037  *√3^2/20+s_2^2/20

  = 1.64

The endpoints of the confidence interval for u_1 — u_2 are:  

(x_1 — x_2) — E = (40 — 43) — 1.6423 = —3 — 1.6423= —4.6423

(x_1 - x_2)  + E   = (40 — 43) + 1.6423 = —3 + 1.6423= —1.3577  

a)We are 95% confident that the average commuting time for route A is between 1.3577 and 4.6423 minutes shorter than the average committing time for rout B.  

(b) No, because the confidence internal does not contain —5, which corresponds with an average of 5 minutes shorter for route A.

3 0
3 years ago
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