Hi!
6 × 8 = 48
The least amount they could've spent is $48. =)
Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
Answer:
16.06
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Answer:
5:20pm
Step-by-step explanation:
120+100=320minutes
320/60=5hrs 20min
12+5:20= 17:20pm or 5:20pm
Answer:
- 5
Step-by-step explanation:
Note that - (- 12) = + 12
Thus
- 17 - (- 12) = - 17 + 12 = - 5
It looks like Tom subtracted 12 from - 17, that is - 17 - 12 = - 29
