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Anastaziya [24]
3 years ago
7

Which expression represents 75 divided by an unknown number? A. 75 – r B. 75 · r C. 75 ÷ r D. 75 + r

Mathematics
2 answers:
Harman [31]3 years ago
7 0
1. c 2. d and 3,a hope i helped

faltersainse [42]3 years ago
6 0

I think this is right

1.c

2.a

3.a

4.d

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Of the sundaes recently sold at Ice Cream Haven, 6 had nuts and 14 did not. Considering this data, how many of the next 10 sunda
Schach [20]

Answer:

3 sundaes will have nuts

Step-by-step explanation:

Note that the total number of sundaes so far is 20, 6 of which had nuts, and 14 didn't.

Therefore the fraction representing the sundaes with nuts would be 6/20 = 3/10.

The fraction without nuts would be 7/10.

The question is asking for you to predict the number of sundaes that will have nuts using these fractions. Out of 10 sundaes, 3 of them will have nuts.

3 0
3 years ago
What is the justification for each step in the solution of the equation? Fill in the empty boxes with the justification.
Mariulka [41]

Answer:

15x - 8 = -12 - 48x + 42

15x - 8 = 30 - 48x

63x - 8 = 30

63x = 38

x = 38/63

3 0
3 years ago
A lumber company is making doors that are 2058.02058.0 millimeters tall. If the doors are too long they must be trimmed, and if
nataly862011 [7]

Answer:

t=\frac{2044-2058}{\frac{17}{\sqrt{15}}}=-3.190    

df=n-1=15-1=14  

p_v =P(t_{(14)}    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly lower than 2058 mm at 5% of signficance.  

Step-by-step explanation:

Data given and notation    

\bar X=2044 represent the sample mean    

s=17 represent the sample standard deviation    

n=15 sample size    

\mu_o =2058 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is lower than 2058 mm, the system of hypothesis are :    

Null hypothesis:\mu \geq 2058    

Alternative hypothesis:\mu < 2058    

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{2044-2058}{\frac{17}{\sqrt{15}}}=-3.190    

P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=15-1=14  

Since is a one-sided lower test the p value would be:    

p_v =P(t_{(14)}    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly lower than 2058 mm at 5% of signficance.  

8 0
3 years ago
I need help showing steps to solve 36v-12=12
Ad libitum [116K]
36v - 12 = 12 .....add 12 to both sides
36v - 12 + 12 = 12 + 12...simplify
36v = 24...divide both sides by 36
(36/36)v = 24/36
v = 2/3 <===
8 0
3 years ago
Read 2 more answers
I don't know how to find the value of the missing variable​
vekshin1

Answer:

whats the question your having trouble with?

5 0
4 years ago
Read 2 more answers
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