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Butoxors [25]
3 years ago
14

This is my last question i need help with ops help SOMEONEEEE

Mathematics
1 answer:
bezimeni [28]3 years ago
7 0

Answer:

Isabelle is correct, its enough to find each angle. We know in a triangle theres 180 degrees expecially in straight lines, in NP and PQ there is two right angles making them similar.

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How to simplify the complex number (9 - 2i) - (-2 + 6i) ?
matrenka [14]
(9 - 2i) - (-2 + 6i) \\ \\ 9 - 2i + 2 - 6i \\ \\ (9+2) + (-2i - 6i) \\ \\ 11 - 8i \\ \\ Answer: \fbox {11 - 8i}
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3 years ago
If ΔABC is dilated by a scale factor of 2 with a dilation center of A, what will be the coordinates of point B'?
ryzh [129]
They are (0,6) because if the center of dilation is point A which means it does not change, while both other points increase their distance from point A by a factor of two (double)
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3 years ago
What is the value of y?<br><br> Enter your answer, as an exact value, in the box.
mylen [45]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
4 years ago
A) Find the area<br>B) Find the perimeter ​
Archy [21]

Answer:

A)

A1= 64

A2= 40

B)

P= 56(of whole shape)

Step-by-step explanation:

A squares area is a side squared so 8^2= 64, and it is also shown that a side of the square is the base of the parallelogram. The area of a parallelogram is b*h so (square side)(8) * height(5)= 40.

Since a parallelograms opposite sides are congruent, 8+8=16, and the other two sides need to be congruent and equal to 40-16(24), therefore the sides are both 12.

Then to calculate the perimeter just count up the side lengths, 8+8+8+12+8+12=56

4 0
3 years ago
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