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masha68 [24]
4 years ago
9

Help please 15 points

Mathematics
1 answer:
krek1111 [17]4 years ago
8 0

angle AOC = 85 degree and

angle AOC = angle AOB + angle BOC

85=4x-15 +2x+ 10

85 = 6x -5

6x = 90

x = \frac{90}{6}

x=15

putting the value of x in the equation of the angleAOB and angle BOC,we get:-

angle AOB = 4x-15

= 4×15-15

=60-15

angle AOB = 45 degree.

angle BOC =2x+10

= 2×15+10

= 30+10

angle BOC = 40 degree.

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26.3 rev/min

Step-by-step explanation:

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3 years ago
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Which correct variables describes the slope?<br> A.X/Y<br> B.Y/X<br> C.W/Z<br> D.Z/W
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6 0
3 years ago
Bonjour je suis en 3 ème pouvez vous m'aider s'il vous plaît une voiture met 2 h 30 pour faire 200 km 1. Calculer sa vitesse moy
Lemur [1.5K]

Répondre:

Explication étape par étape:

Vitesse = Distance / Temps

Distance donnée = 200 km

Durée = 2 h 30

Convertir le temps en heures

Depuis 60 minutes = 1h

2 heures 30 minutes = 2+ (30/60)

2h30 = 2 + 1/2 hors

2 heures 30 minutes = 2,5 heures

Vitesse en km / h = 200 km / 2,5 h

Vitesse en km / h = 80 km / h

D'où sa vitesse moyenne en km / h est de 80 km / h

a) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 3h15

Temps = 3 15/60 h

Durée = 3,25 h

Distance = 80 * 3,25

Distance parcourue en 3h15 = 260 km

b) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 42 minutes

Durée = 42/60 h

Distance = 80 * 42/60

Distance = 3360/60

Distance = 56 km

Distance parcourue en 42 minutes = 56 km

c) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 3 h 36 minutes

Temps = 3 36/60 h

Durée = 3,6 h

Distance = 80 * 3,6

Distance = 288 km

Distance parcourue en 3 h 36 min = 288 km

d) Distance donnée = 540 km

Vitesse = 80 km / h

Temps = Distance / Vitesse

Heure = 540/80

Temps = 6,75 heures

Par conséquent, le temps nécessaire pour parcourir 540 km est de 6,75 heures

7 0
3 years ago
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