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masha68 [24]
4 years ago
9

Help please 15 points

Mathematics
1 answer:
krek1111 [17]4 years ago
8 0

angle AOC = 85 degree and

angle AOC = angle AOB + angle BOC

85=4x-15 +2x+ 10

85 = 6x -5

6x = 90

x = \frac{90}{6}

x=15

putting the value of x in the equation of the angleAOB and angle BOC,we get:-

angle AOB = 4x-15

= 4×15-15

=60-15

angle AOB = 45 degree.

angle BOC =2x+10

= 2×15+10

= 30+10

angle BOC = 40 degree.

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levacccp [35]

Answer:

f(x) = 2[\frac{3^x}{9}] + 2

f(x) = 8(4)^x

Step-by-step explanation:

Given

f(x) = 2(3)^{x-2} + 2

f(x) = \frac{1}{2}(4)^{x+2}

Required

Remove the h component

In a function, the h component is highlighted as:

f(x) = a^{x+h}

So, we have:

f(x) = 2(3)^{x-2} + 2

Split the exponents using the following law of indices:

a^m/a^n = a^{m-n}

f(x) = 2*\frac{3^x}{3^2} + 2

f(x) = 2*\frac{3^x}{9} + 2

f(x) = 2[\frac{3^x}{9}] + 2

<em>The h component has been removed</em>

f(x) = \frac{1}{2}(4)^{x+2}

Split the exponent using the following law of indices

a^{m+n} =a^m * a^n

So, we have:

f(x) = \frac{1}{2}(4)^x * 4^2

Express 4^2 as 16

f(x) = \frac{1}{2}(4)^x * 16

Divide 16 by 2

f(x) = 8(4)^x

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